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Elanso [62]
3 years ago
10

4(y-3) + 3(y+4). solve the equation fast and ill mark you brainliest

Mathematics
2 answers:
shusha [124]3 years ago
8 0

Answer:

hope it helps you.......

Pepsi [2]3 years ago
3 0

Step-by-step explanation:

4(y-3) + 3(y+4)

4y-12+ 3y+12

4y+3y-12+12

7y

I hope it helped U

stay safe stay happy

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in Aprils DVD collection she has 8 action dvds 12 comedy DVDs 7 romance DVDs what percent of April's DVD collection are comedies
Artyom0805 [142]

Answer:

Step-by-step explanation:

<h3><u><em>Figure it out but your self.... Nawll i'm jp get it off google</em></u></h3>
7 0
3 years ago
Help plzzzzzzzzzzzzzzzzz
alekssr [168]

Answer:

this answer is -1.8

Step-by-step explanation:

because you add and subtract all of them

6 0
3 years ago
Read 2 more answers
Suppose the mean height of women age 20 years or older in a certain country is 62.7 inches. One hundred randomly selected women
zmey [24]

Answer: No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

Step-by-step explanation:

Since we have given that

H_0:\mu =62.7\\\\H_a:\mu \neq 62.7

Mean height = 61.5 inches

Standard deviation = 4.4 inches

n = 100

So, test statistic value would be

z=\dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{61.5-62.7}{\dfrac{4.4}{\sqrt{100}}}\\\\z=\dfrac{-1.2}{0.44}\\\\z=-2.727

At 10% level of significance, in two tail test ,

z = 1.28

Since 1.28 > -2.727

So, we will accept the null hypothesis.

Hence, No, the data provided is not sufficient evidence to conclude that the mean height of women in the city differs from the national mean.

7 0
4 years ago
13 1/2 - 7 3/8<br><br> what is the answer?
hoa [83]
I’m pretty sure the answer is 6.125
6 0
3 years ago
A total of 366 tickets were sold for the school day they were pay they were either adults tickets or students tickets.the number
JulijaS [17]

Answer:

122

Step-by-step explanation:

366 divided by 3


6 0
3 years ago
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