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2 years ago

B is the midpoint of AC. If AB = x + 5 and AC = 3x - 6, find BC.

Mathematics

2 answers:

Likurg_2 [28]2 years ago

8 0

Answer:

21 units

Step-by-step explanation:

Since B is the midpoint, we have:

AB = BC = AC/2

Substitute and solve for x:

x + 5 = (3x - 6)/2
3x - 6 = 2x + 10
3x - 2x = 10 + 6
x = 16

Find BC:

BC = AB = 16 + 5 = 21

Bas_tet [7]2 years ago

4 0

Hey there! I'm happy to help!

We see that at AB is halfway across our line. We see that AC is the total line.

So, to find the other half, we have to subtract AB from AC, which will give us the value of BC.

We first will subtract our x values.

3x-x=2x

And then we subtract our numbers.

-6-5=-11

So, BC is 2x-11.

Have a wonderful day and keep on learning! :D

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Ivan evaluated the expression 8+12÷3×2 and got 10. What mistake did he make?

lesya [120]

Ivan forgot to follow PEMDAS
Division first
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3 years ago

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|x-1|+2<4 solving for x

Ganezh [65]

Answer:

x < 3 and x > -1

Step-by-step explanation:

Step 1: Subtract 2 from both sides.

$|x-1| + 2 - 2 < 4 - 2$
$|x-1|$

Step 2: Solve absolute value.

We know x - 1 < 2 and x - 1 > -2.

Condition 1:

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Condition 2:

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$x - 1 + 1 > -2 + 1$ (Add 1 to both sides)
$x>-1$

Therefore, the answer is x < 3 and x > -1.

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2 years ago

Claris was asked the expression 6 times y plus y times 4

lianna [129]

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3 years ago

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If a= .75 and b= .50, what is the perimeter of the rectangle?

Lerok [7]

Answer:

C. 14 inches

Step-by-step explanation:

The perimeter is double the sum of length and width:

P = 2((4a +3) +(6b -2) = 8a +12b +2

For the given values, this is ...

P = 8(0.75) +12(0.50) +2 = 6 + 6 + 2 = 14

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3 0

3 years ago

Find the missing side of the triangle. leave your answer in simplest radical form

KIM [24]

missing side is $x} = 10.15$ mi .

Step-by-step explanation:

Here we have the following info from the figure: A right angled triangle with following dimensions

$Perpendicular = x$

$base = \sqrt{122}$

$Hypotenuse = 15$

By Pythagoras Theorem :

$Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $Hypotenuse^2 = Perpendicular^2 + base^2$

⇒ $15^2 = x^2 + (\sqrt{122})^2$

⇒ $225 = x^2 + 122$

⇒ $x^2 = 225-122$

⇒ $x^2 = 103$

⇒ $(x^2)^\frac{1}{2} = (103)^\frac{1}{2}$

⇒ $x} = (103)^\frac{1}{2}$

⇒ $x} = 10.15$

Therefore, missing side is $x} = 10.15$ mi .

8 0

3 years ago