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2 years ago

7x2 - 4x +10+ 3x2 – 8

Mathematics

2 answers:

kupik [55]2 years ago

8 0

Answer: 22-4x when you simplify it all.

Orlov [11]2 years ago

6 0

If in the question it is 7x^2 and 3x^2, then

7x^2 - 4x + 10 + 3x^2 - 8

Re grouping the variables,

7x^2 + 3x^2 - 4x + 10 - 8

10x^2 - 4x + 2

The above would be the answer if the question was 7x^2 - 4x +10 +3x^2 - 8

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Answer:

7*5^10=68,359,375

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What is 1/8 of a full rotation

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45°

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2 years ago

Please it's urgent I really need answers

WITCHER [35]

(c)

We notice that they already have common denominators, therefore we can just add the numerators up.

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-Hunter

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2 years ago

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(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

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3 years ago

6 1/2 - 7/8 : 5 11/16

Komok [63]

Answer:

Step-by-step explanation:

brainly.com/question/6752935

hope this helps

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