1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrej [43]
3 years ago
6

What is the difference of the rational expressions below?

Mathematics
1 answer:
Korolek [52]3 years ago
4 0

Answer:

in the pic

Step-by-step explanation:

answer A

.....

You might be interested in
A phone company charges $0.45 for the first minute and $0.35 for each additional minute for a long distance call. Which numerica
Vinvika [58]

0.45+19(0.35)

Total cost $7.10 (0.45+6.65)

8 0
3 years ago
Read 2 more answers
What is the area of this figure?<br><br><br> 49.5 in²<br><br> 66.5 in²<br><br> 84 in²<br><br> 91 in²
Nookie1986 [14]
D 19 in2
find the area of a square, width times height
then find the area of the triangle, width times height divided by 2
6 0
3 years ago
Read 2 more answers
What is the answer to this question (3x3)+7-7=
exis [7]

Answer:

9

Step-by-step explanation:

Assuming x is the multiplication symbol, you would multiply 3 and the other 3 together. This leaves you with 9+7-7. Since 7-7=0 you can just get rid of both sevens completely. Now you are only left with 9.

6 0
3 years ago
Read 2 more answers
One division of a large defense contractor manufactures telecommunication equipment for the military. This division reports that
Zielflug [23.3K]

Answer:

At the 95% confidence level, management should not conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components, since the upper bound of the confidene interval, which is 0.1339, is higher than 0.12.

Step-by-step explanation:

To reach a conclusion, we have to observe the confidence interval.

Should management conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components?

Is the upper bound of the confidence interval lower than 12% = 0.12?

If yes, it should conclude that this percentage is lower.

Otherwise, it cannot conclude.

Confidence interval:

0.0758 to 0.1339

0.1339 is higher than 0.12.

So.

At the 95% confidence level, management should not conclude that the percentage of rework for electrical components is lower than the rate of 12% for non-electrical components, since the upper bound of the confidene interval, which is 0.1339, is higher than 0.12.

6 0
3 years ago
Read 2 more answers
Consider the following initial value problem, in which an input of large amplitude and short duration has been idealized as a de
Ganezh [65]

Answer:

a. \mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}

b. \mathbf{y(t) = \{7e^t + e^3 u (t-3)-7\}e^{-t}}

Step-by-step explanation:

The initial value problem is given as:

y' +y = 7+\delta (t-3) \\ \\ y(0)=0

Applying  laplace transformation on the expression y' +y = 7+\delta (t-3)

to get  L[{y+y'} ]= L[{7 + \delta (t-3)}]

l\{y' \} + L \{y\} = L \{7\} + L \{ \delta (t-3\} \\ \\ sY(s) -y(0) +Y(s) = \dfrac{7}{s}+ e ^{-3s} \\ \\ (s+1) Y(s) -0 = \dfrac{7}{s}+ e^{-3s} \\ \\ \mathbf{Y(s) = L \{y(t)\} = \dfrac{7}{s(s+1)}+ \dfrac{e^{-3s}}{s+1}}

Taking inverse of Laplace transformation

y(t) = 7 L^{-1} [ \dfrac{1}{(s+1)}] + L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{(s+1)-s}{s(s+1)}] +L^{-1} [\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7L^{-1} [\dfrac{1}{s}-\dfrac{1}{s+1}] + L^{-1}[\dfrac{e^{-3s}}{s+1}] \\ \\ y(t) = 7 [1-e^{-t} ] + L^{-1} [\dfrac{e^{-3s}}{s+1}]

L^{-1}[\dfrac{e^{-3s}}{s+1}]

L^{-1}[\dfrac{1}{s+1}] = e^{-t}  = f(t) \ then \ by \ second \ shifting \ theorem;

L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{f(t-3) \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

L^{-1}[\dfrac{e^{-3s}}{s+1}] = \left \{ {{e^{(-t-3)} \ \ \ t>3} \atop {0 \ \ \ \ \ \  \ \  \ t

= e^{-t-3} \left \{ {{1 \ \ \ \ \  t>3} \atop {0 \ \ \ \ \  t

= e^{-(t-3)} u (t-3)

Recall that:

y(t) = 7 [1-e^{-t} ] + L^{-1} [\dfrac{e^{-3s}}{s+1}]

Then

y(t) = 7 -7e^{-t}  +e^{-(t-3)} u (t-3)

y(t) = 7 -7e^{-t}  +e^{-t} e^{-3} u (t-3)

\mathbf{y(t) = \{7e^t + e^3 u (t-3)-7\}e^{-t}}

3 0
3 years ago
Other questions:
  • How do you do this? Thanks for your time and effort!
    15·2 answers
  • currently 96 members participate in the morning workout and this # has been increasing by 2 ppl per week. currently 80 ppl parti
    11·1 answer
  • Suppose that a family wants to start a college fund for their child. If you invest in an account that pays 5.5% and want the fun
    15·1 answer
  • Abby works in the sales department. This month the company is offering a 3-week paid vacation to every employee who sells 230% o
    14·1 answer
  • Can some one please help me on C. just C
    12·1 answer
  • Help please! i’ll give brainlest or whatever it’s called
    10·2 answers
  • Can someone please help me with the second question in the picture.
    6·1 answer
  • What is the unit rate for 280 students/8 buses?
    8·2 answers
  • Write an<br> expression to represent:<br> The sum of ten and the quotient of a number and 6.
    11·1 answer
  • Triangle is dilated using as the center of dilation with scale factor 2. The image is triangle A'B'C'. Clare says the two triang
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!