All categories

3 years ago

What is the difference of the rational expressions below?

Mathematics

1 answer:

Korolek [52]3 years ago

4 0

Answer:

in the pic

Step-by-step explanation:

answer A

.....

You might be interested in

Simplify -3p - 2m + 8p - 7m

Nadya [2.5K]

After you combine like terms you will get 5p - 9m.

-3p + 8p is the same thing as 8p - 3, so you get 5p.
-2m + (-7m) is -9m

-3p and 8p are like terms.
-2m and -7m are also like terms.

7 0

3 years ago

Find the vertex, focus, directrix, and focal width of the parabola. (5 points)

Anarel [89]

$\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf -\cfrac{1}{20}x^2=y\implies \cfrac{x^2}{-20}=y\implies x^2=-20y\implies (x-0)^2=-20(y-0) \\\\\\ (x-\stackrel{h}{0})^2=4(\stackrel{p}{-5})(y-\stackrel{k}{0})$

something noteworthy is that the squared variable is the "x", thus the parabola is a vertical one, the "p" value is negative, so is opening downwards, and the h,k is pretty much the origin,

vertex is at (0,0)

the focus point is "p" or 5 units down from there, namely at (0, -5)

the directrix is "p" units on the opposite direction, up, namely at y = 5

the focal width, well, |4p| is pretty much the focal width, in this case, is simply yeap, you guessed it, 20.

8 0

3 years ago

5. a. The area of an isosceles triangle is 60cm² and its base is 10cm. Find the length of its equal side.

Sindrei [870]

Answer:

H = 12cm

I hope I was able to help

4 0

2 years ago

The vertices of triangle IJK have coordinates I(−5, −2), J(−5, −4), and K(−4, −4).

AnnZ [28]

The answer is equal to D.

3 0

3 years ago

At a sport clubhouse the coach wants to rope off a rectangular area that is adjacent to the building. He uses the length of the

Furkat [3]

Answer:

w < 8 meters ( w must be greater than 0 because length cannot be 0)

Step-by-step explanation:

One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).

Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:

Rope Needed = 23 + 2w < 39

Simplifying:

$23 + 2w < 39\\2w < 39 - 23\\2w < 16\\w < 8$

The range of possible values of w is $w$ meters (of course w has to be greater than 0)

5 0

3 years ago