Question

RS=7y+4, ST=3y+6, and RT=90

Answer 1

Answer:

If it is a straight line then ;

RT= RS+ST

90=(7y+4) + (3y+6)

90 = 10y + 10

10y= 90 – 10

10y = 80

y= 80 / 10

y =8

ST = 3y+6= 3(8)+6= 24 +6 = 30

RS = 7y +4 = 7(8) + 4 = 56 +4 = 60

I hope I helped you^_^