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3 years ago

58-(1/4)2 i dont get how to solve this

Mathematics

2 answers:

Lunna [17]3 years ago

8 0

Answer:

57.5 or 57 1/2

Step-by-step explanation:

1. Start with 1/4*2 due to the ”order of operation rules”. You then get 1/2.

2. Then, continue to do 58-1/2 to get 57.5 or 57 1/2

xeze [42]3 years ago

5 0

Answer:

57.5

Step-by-step explanation:

First you would have to multiply following PEMDAS so

(1/4)(2)

=0.5

Then subtract 58 and 0.5

58-0.5

=57.5

and thats your answer

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ILL GIVE BRAINLIEST!!!!!! Please explain!! Thank you!!

Bumek [7]

Answer:

The answer would be C

Step-by-step explanation:

He started at 250 lbs. He is losing 3 lbs every week.

So it would be y=250(beginning weight)-3x(how much he's losing every week)

Hope this helped :)

4 0

3 years ago

Read 2 more answers

Will give brainliest to correct answer! Given that cos Ф=-8/17 and sin Ф is negative, determine the value of tan Ф.

Kipish [7]

Answer: option 3 is the correct answer

Step-by-step explanation:

Let us look at the various trigonometric ratios

Sin Ф = opposite side/ hypotenuse

Cos Ф = adjacent side / hypotenuse

Tan Ф = opposite side / adjacent side

Therefore, tan Ф = sin Ф / cos Ф

This means that if cos Ф=-8/17 and sin Ф is negative, then the hypotenuse is negative

To determine the adjacent side, we will apply Pythagoras theorem

Hypotenuse ^2 = opposite ^2 + adjacent ^2

-17^2 = 8^2 + adjacent^2

adjacent^2 = 289 - 64 = 225

adjacent = √225 = 15

tan Ф = 8/15

5 0

3 years ago

Juan made 13 out of 20 free throws. If Botina shoots 25 free thows, what's the minimum number she has to make in order to have a

Dahasolnce [82]

Answer:

the answer is 17

Step-by-step explanation:

juans free throw % is 65 so botina has to make 17 out of 25 to get a better percent which is 68

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3 years ago

Read 2 more answers

Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p

scZoUnD [109]

Answer:

The probability that they will teach different courses is $\frac{2}{3}$ .

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here x represents the course taught by the first part-time instructor and y represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events E is the ratio of the number of favorable outcomes to the total number of outcomes.

$P(E)=\frac{n(E)}{N}$

Compute the probability that they will teach different courses as follows:

$P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}$

Thus, the probability that they will teach different courses is $\frac{2}{3}$ .

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3 years ago

Based on a Comcast survey, there is a 0.8 probability that a randomly selected adult will watch prime-time TV live, instead o

klio [65]

Answer: Our required probability is 0.004672.

Step-by-step explanation:

Since we have given that

Number of adults = 7

Probability of getting adult will watch prime time TV live = 0.8

We need to find the probability that fewer than 3 of the selected adults watch prime time live.

We will use "Binomial Distribution":

here, n = 7

p = 0.8

So, P(X<3)=P(X=0)+P(X=1)+P(X=2)

So, it becomes,

$P(X=0)=(1-0.8)^7=0.2^7=0.0000128$

$P(X=1)=^7C_1(0.8)(0.2)^6=0.0003584\\\\P(X=2)=^7C_2(0.8)^2(0.2)^5=0.0043$

So, probability that fewer than 3 of the selected adult watch prime time live is given by

$0.0000128+0.0003584+0.0043=0.004672$

Hence, our required probability is 0.004672.

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3 years ago