All categories

3 years ago

In the figure, angle A measures 41° and angle D measures 32°. What is the measurement of angle E?

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

6 0

All the angles of a triangle add up to 180 degrees.

We know <A= 41 and <B=90 (right angle mark)

Find <C.

41+90+<C= 180

131+<C= 180

Subtract by 131 on both sides.

<C= 49

All the angles on that bottom line are supplementary because a line is a straight angle equal to 180 degrees.

So,

<C+<E+<D= 180 Plug in the values you know.

49+<E+32= 180

81+<E=180

Subtract 81 on both sides.

<E= 99 degrees.

I hope this helps!
~kaikers

Jlenok [28]3 years ago

3 0

Interior angles of a triangle, when added, = 180
so < A + < B + < C = 180
41 + 90 + < C = 180
131 + < C = 180
< C = 180 - 131
< C = 49

< C + < D + < E = 180.....because when added they form a line
49 + 32 + < E = 180
81 + < E = 180
< E = 180 - 81
< E = 99 <======

You might be interested in

Find the following when a = -1, b = 2, c = -1/4<br> (4b - 3)/(2a) -1

Katena32 [7]

We substitute the given into the equation
given: a=-1, b=2, c= $\frac{-1}{4}$
=( $\frac{4b-3}{2a}$ -1
= $\frac{4(2)-3}{2(-1)}$ -1
= $\frac{8-3}{-2}$ -1
= $\frac{5}{-2}$ -1
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:
$\frac{5}{-2}$ =-2.5
Equation=-2.5-1=-3.5
OR Common Denominator:
= $\frac{5}{-2}$ $\frac{-1}{1}$ × $\frac{-2}{-2}$ (denominator should be -2=common)
= $\frac{5}{-2}$ + $\frac{2}{-2}$
= $\frac{7}{-2}$
which also = to -3.5

3 0

3 years ago

How do i make a table of values for each function rule and then graph the function for these examples:

Sholpan [36]

$\bf \begin{array}{ccllll}
y=1.5x-3\\
\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\

x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-3&1.5(-3)-3\\
-2&1.5(-2)-3\\
-1&1.5(-1)-3\\
0&1.5(0)-3\\
1&1.5(1)-3\\
...&...
\end{array}$ $\bf \begin{array}{ccllll}
y=-x^2+4\\
\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\

x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
-3&-(-3)^2+4\\
-2&-(-2)^2+4\\
-1&-(-1)^2+4\\
0&-(0)^2+4\\
1&-(1)^2+4\\
...&...
\end{array}$

and so on, and then, you graph those x,y coordinates

5 0

3 years ago

Noah and Lin are each trying to solve the equation x² - 6x + 10 = 0. They know that the solutions to x² = - 1 are i and -i, but

Leviafan [203]

Answer:

Solving the equation $x^2 - 6x + 10 = 0$ we get $x=3+i \ , \ x=3-i$

Step-by-step explanation:

Noah's step to solve the equation $x^2 - 6x + 10 = 0$ are:

$x^2 - 6x + 10 = 0\\x^2 - 6x = -10\\x^2 - 6x + 9 = -10 + 9\\(x-3)^2 = -1$

The next step is to take square root on both sides because: $\sqrt{x^2}=x$

$\sqrt{(x-3)^2}=\sqrt{-1} \\x-3=\pm\sqrt{-1} \\x=\pm(\sqrt{-1})+3 \\$

Now, we know that: $\sqrt{-1}=i$

$x=\pm(i)+3\\x=3+i \ , \ x=3-i$

So, Solving the equation $x^2 - 6x + 10 = 0$ we get $x=3+i \ , \ x=3-i$

8 0

3 years ago

Solve the system of equations. y = 6x - 27 y = 4x - 17

NeTakaya

Y=6x-27...........(1)
y=4x-17...........(2)

By comparison
6x-27=4x-17
=> 2x=10 => x=5
Substitute x=5 into (1)
y=6(5)-27=3
Check:
y=4(5)-17=3 as well.

5 0

3 years ago

Read 2 more answers

Find the sum of the sequence 38+39+40+........+117

leva [86]

The answer is 6200
i think
your welcome

6 0

3 years ago