All categories

3 years ago

A rectangle has sides measuring (4x + 5) units and (3x + 10) units.

Mathematics

1 answer:

grin007 [14]3 years ago

5 0

Answer:

The area is just length times width: (4x+5)(3x+10)=12x2+55x+50.

Step-by-step explanation:

You might be interested in

1/5 (4-3x) = 1/7 (3x - 4) pls solve

natulia [17]

$\huge \boxed{\mathfrak{Question} \downarrow}$

$\large\sf\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$\frac{1}{5} (4 - 3x) = \frac{1}{7} (3x - 4) \\$

Use the distributive property to multiply 1/5 by 4-3x.

$\frac{1}{5}\times 4+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and 4 to get 4/5.

$\frac{4}{5}+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right) \\$

Multiply 1/5 and -3 to get -3/5.

$\frac{4}{5}+\frac{-3}{5}x=\frac{1}{7}\left(3x-4\right) \\$

Use the distributive property to multiply 1/7 by 3x-4.

$\frac{4}{5}-\frac{3}{5}x=\frac{1}{7}\times 3x+\frac{1}{7}\left(-4\right) \\$

Multiply 1/7 and 3 to get 3/7 & 1/7 × -4 to get -4/7.

$\frac{4}{5}-\frac{3}{5}x=\frac{3}{7}x-\frac{4}{7} \\$

Subtract $\frac{3}{7}x\\$ from both sides.

$\frac{4}{5}-\frac{3}{5}x-\frac{3}{7}x=-\frac{4}{7} \\$

Combine $-\frac{3}{5}x\\$ and $-\frac{3}{7}x\\$ to get $-\frac{36}{35}x\\$ .

$\frac{4}{5}-\frac{36}{35}x=-\frac{4}{7} \\$

Subtract 4/5 from both sides.

$-\frac{36}{35}x=-\frac{4}{7}-\frac{4}{5} \\$

The least common multiple of 7 and 5 is 35. Convert -4/7 and 4/5 to fractions with denominator 35.

$-\frac{36}{35}x=-\frac{20}{35}-\frac{28}{35} \\$

Because $-\frac{20}{35} \\$ and $\frac{28}{35}\\$ have the same denominator, subtract them by subtracting their numerators.

$-\frac{36}{35}x=\frac{-20-28}{35} \\$

Subtract 28 from -20 to get -48.

$-\frac{36}{35}x=-\frac{48}{35} \\$

Multiply both sides by $-\frac{35}{36}\\$ , the reciprocal of $-\frac{36}{35}\\$ .

$x=-\frac{48}{35}\left(-\frac{35}{36}\right) \\$

Multiply $-\frac{48}{35}\\$ by $-\frac{35}{36}\\$ by multiplying the numerator by the numerator and the denominator by the denominator.

$x=\frac{-48\left(-35\right)}{35\times 36} \\$

Carry out the multiplications in the fraction $\frac{-48\left(-35\right)}{35\times 36}\\$ .

$x=\frac{1680}{1260} \\$

Reduce the fraction 1680/1260 to its lowest terms by extracting and cancelling out 420.

$\huge \boxed{ \boxed{ \bf \: x=\frac{4}{3} \approx \: 1.33}}$

3 0

3 years ago

Read 2 more answers

Work out the area of a circle with a radius 6.2cm, take n/pi to be 3.142 and give your answer to 2 decimal places.

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

Area is pi times r squared. I don't know how to write that on the keyboard. Take your pi(3.142) times the radius(6.2)squared. Pemdas tell us to do exponents first, so 6.2 squared is 38.44. To square a number, just multiply it times itself. So now, we have pi(3.142) times the squared radius(38.44). So, 3.142X38.44=

120.778 Second place is seven followed by eight. Round up. 120.78

3 0

4 years ago

What is limit of (startstartfraction negative sine (startfraction pi x over 3 endfraction) overover 3 endendfraction) as x appro

Nutka1998 [239]

I'm guessing your limit is

$\displaystyle \lim_{x\to5} \frac{-\sin\left(\frac{\pi x}3\right)}3$

The limand is continuous at x = 5, so we can evaluate the limit directly by substituting x = 5:

$\displaystyle \lim_{x\to5} \frac{-\sin\left(\frac{\pi x}3\right)}3 = -\frac13 \sin\left(\frac{5\pi}3\right) = -\frac13 \times \left(-\frac{\sqrt3}2\right) = \boxed{\frac1{2\sqrt3}} = \boxed{\frac{\sqrt3}6}$