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3 years ago

= 1} " alt=" n - \sqrt{c + 5 = 1} " align="absmiddle" class="latex-formula">
in the equation above, C is a constant. If n= 5, what is the value of c?

Could you say how you got rid of the negative sign in front of the square root in the process plz

SAT

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

c is 11

Explanation:

$n - \sqrt{c + 5 } = 1 \\ 5 - \sqrt{c + 5} = 1 \\$

make -√c+5 the subject:

$- \sqrt{c + 5} = 1 - 5 \\ - \sqrt{c + 5} = - 4$

divide through out by -1 :

$\frac{ - \sqrt{c + 5} }{ - 1} = \frac{ - 4}{ - 1} \\ \\ \sqrt{c + 5} = 4$

square both sides;

${( \sqrt{c + 5} )}^{2} = {4}^{2} \\ c + 5 = 16 \\ c = 11$

Salsk061 [2.6K]3 years ago

7 0

Answer:

c=11

Explanation:

$n - \sqrt{c + 5} = 1$

$5 - \sqrt{c + 5} = 1$

Add sqr root of c+5 to both sides

$5 = 1 + \sqrt{c + 5}$

$4 = \sqrt{c + 5}$

$16 = c + 5$

$c = 11$

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If 3x − y = 12, what is the value of 8^x/2^y?

ivanzaharov [21]

Answer:

Explanation:

Let's solve the equation to be written as y in terms of x by adding y to and subtracting 12 from both sides:

3x - y = 12

3x - 12 = y

Now, replace y in the other expression that we want to find ( $8^x/2^y$ ) with this expression 3x - 12:

$8^x/2^y$

$8^x/2^{3x-12}$

Now, we also know that 8 = 2³, so substitute 2³ for 8 in the expression:

$8^x/2^{3x-12}$

$(2^3)^x/2^{3x-12}=2^{3x}/2^{3x-12}$

Remember that when dividing powers with the same base (in this case, the common base is 2), the result will be a single power whose exponent is the difference of the other two powers. Here, then we have:

$2^{3x}/2^{3x-12}=2^{3x-(3x-12)}=2^{12}$