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Vinvika [58]
3 years ago
8

= 1} " alt=" n - \sqrt{c + 5 = 1} " align="absmiddle" class="latex-formula">
in the equation above, C is a constant. If n= 5, what is the value of c?

Could you say how you got rid of the negative sign in front of the square root in the process plz

​
SAT
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

<u>c</u><u> </u><u>is</u><u> </u><u>1</u><u>1</u>

Explanation:

n - \sqrt{c + 5 } = 1  \\ 5 -  \sqrt{c + 5}  = 1 \\

make -√c+5 the subject:

-  \sqrt{c + 5}  = 1 - 5 \\  -  \sqrt{c + 5}  =  - 4

divide through out by -1 :

\frac{ -  \sqrt{c + 5} }{ - 1}  =  \frac{ - 4}{ - 1}  \\  \\    \sqrt{c + 5}  = 4

square both sides;

{( \sqrt{c + 5} )}^{2}  =  {4}^{2}  \\ c + 5 = 16 \\ c = 11

Salsk061 [2.6K]3 years ago
7 0

Answer:

c=11

Explanation:

n -  \sqrt{c  +  5}  = 1

5 -  \sqrt{c + 5}  = 1

Add sqr root of c+5 to both sides

5 = 1 +  \sqrt{c + 5}

4 =  \sqrt{c + 5}

16 = c + 5

c = 11

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