Question

= 1} " alt=" n - \sqrt{c + 5 = 1} " align="absmiddle" class="latex-formula">
in the equation above, C is a constant. If n= 5, what is the value of c?

Could you say how you got rid of the negative sign in front of the square root in the process plz

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Answer 1

Answer:

c is 11

Explanation:

$n - \sqrt{c + 5 } = 1 \\ 5 - \sqrt{c + 5} = 1$

make -√c+5 the subject:

$- \sqrt{c + 5} = 1 - 5 \\ - \sqrt{c + 5} = - 4$

divide through out by -1 :

$\frac{ - \sqrt{c + 5} }{ - 1} = \frac{ - 4}{ - 1} \\ \\ \sqrt{c + 5} = 4$

square both sides;

${( \sqrt{c + 5} )}^{2} = {4}^{2} \\ c + 5 = 16 \\ c = 11$

Answer 2

Answer:

c=11

Explanation:

$n - \sqrt{c + 5} = 1$

$5 - \sqrt{c + 5} = 1$

Add sqr root of c+5 to both sides

$5 = 1 + \sqrt{c + 5}$

$4 = \sqrt{c + 5}$

$16 = c + 5$

$c = 11$