3 years ago

Solve the following system of equations for x: xy = 6 3y = x - 3

Mathematics

1 answer:

liberstina [14]3 years ago

3 0

Answer:

Step-by-step explanation:

rearrange 3y = x-3 as x=3y+3 sub in for x in xy=6

(3y+3)(y)=6

solve by factoring 3y^2+3y-6=0

3(y-1)(y+2) = 0

y= 1, -2

sub y back in to either equation but for ease xy=6

x(1)=6 = 6

x(-2)=6 = -3

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