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3 years ago

5

Question 3(Multiple Choice Worth 2 points)

1 answer:

vodomira [7]3 years ago

6 0

Answer:

y = $\frac{4}{3}$ x - 4

Step-by-step explanation:

Given

4x - 3y = 12 ( subtract 4x from both sides )

- 3y = - 4x + 12 ( divide terms by - 3 )

y = $\frac{4}{3}$ - 4 ← in the form y = mx + b

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4 years ago

What is -18+8x>__50

qwelly [4]

Step-by-step explanation:

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3 years ago

H(x) = x2 + 1 k(x) = x – 2 (h + k)(2) = (h – k)(3) = Evaluate 3h(2) + 2k(3) =

matrenka [14]

For this case we have the following functions:

$h (x) = x ^ 2 + 1$

$k (x) = x - 2$

We must perform each of the operations shown.

We have then:

For (h + k) (2):

$(h + k) (x) = h (x) + k (x)$

$(h + k) (x) = (x ^ 2 + 1) + (x - 2)$

$(h + k) (x) = x ^ 2 + x - 1$

Evaluating for x = 2 we have:

$(h + k) (2) = 2 ^ 2 + 2 - 1$

$(h + k) (2) = 4 + 2 - 1$

$(h + k) (2) = 5$

For (h - k) (3):

$(h - k) (x) = h (x) -k (x)$

$(h - k) (x) = (x ^ 2 + 1) - (x - 2)$

$(h - k) (x) = x ^ 2 - x + 3$

Evaluating for x = 3 we have:

$(h - k) (3) = 3 ^ 2 - 3 + 3$

$(h - k) (3) = 9 - 3 + 3$

$(h - k) (3) = 9$

For 3h (2) + 2k (3):

$3h (2) + 2k (3) = 3 (2 ^ 2 + 1) + 2 (3 - 2)$

$3h (2) + 2k (3) = 3 (5) + 2 (1)$

$3h (2) + 2k (3) = 15 + 2$

$3h (2) + 2k (3) = 17$

Answer:

$(h + k) (2) = 5$

$(h - k) (3) = 9$

$3h (2) + 2k (3) = 17$

4 0

3 years ago

Read 2 more answers