Answer:
We have to multiply
⇒39.6 x 5.20 [ Using traditional method]
Traditional method: used by humans when they learnt counting and when fraction came into existence.Suppose something(Area of a field) is divided into parts and another thing(Amount of water used in irrigating the field) is divided into parts and then we have to multiply these two numbers.
Answer:
14 pint containers.
Step-by-step explanation:
First we have to convert gallon to quart.
2 gallons = 8 quarts
There are 2 containers that added up to 1 quart, so let's subtract the one quart from the 2 gallons(8 quarts), leaving behind 7 quarts.
The conversion between quarts and pints are 1qt=2pt, according to the key you provided. Then 7 quarts will equal to 14 pints. And therefore, she will need 14 pint containers.
We know that
A quadrilateral is inscribed in a circle if and only if the opposite angles are supplementary. ( Inscribed Quadrilateral Theorem)
so
m∠B+m∠D=180°
2x+(3x-5)=180
5x=180+5
5x=185
x=185/5
x=37°
m∠A=x+5-----> 37+5------> 42°
the answer is
m∠A is 42°
Good evening ,
Answer:
<h2>153 dimes.</h2>
Step-by-step explanation:
1+2+3+...+17 = (17×18)/2 = (17×18)÷2 = 153 dimes.
it’s the sum of 17 terms of a geometric series.
:)
<h3>
Answer: 1</h3>
Point B is the only relative minimum here.
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Explanation:
A relative minimum is a valley point, or lowest point, in a given neighborhood. Points to the left and right of the valley point must be larger than the relative min (or else you'd have some other lower point to negate its relative min-ness).
Point B is the only point that fits the description mentioned in the first paragraph. For a certain neighborhood, B is the lowest valley point so that's why we have a relative min here.
There's only 1 such valley point in this graph.
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Side notes:
- Points A and D are relative maximums since they are the highest point in their respective regions. They represent the highest peaks of their corresponding mountains.
- Points A, C and E are x intercepts or roots. This is where the graph either touches the x axis or crosses the x axis.
- The phrasing "a certain neighborhood" is admittedly vague. It depends on further context of the problem. There are multiple ways to set up a region or interval of points to consider. Though visually you can probably spot a relative min fairly quickly by just looking at the valley points.
- If you have a possible relative min, look directly to the left and right of this point. if you can find a lower point, then the candidate point is <u>not</u> a relative min.
