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3 years ago

Determine whether the graph is the graph of a function. Yes or no.

Mathematics

1 answer:

Contact [7]3 years ago

3 0

I'm pretty sure it is a function!
if you put a vertical line on any point of the function, it does not touch the vertical line in two different places at all! i hope this helps :)

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In some country the budget for defense exceeded the budget for education by $622.7 billion. If x represents the budget for edu

inysia [295]

Answer:

$y = x + \$622.7\ billion$

Step-by-step explanation:

To start with;

Represent the budget of education by x

Represent the budget of defense by y

From the question, we understand that:

y exceeds x by $622.7 billion

Mathematically. this can be represented as:

$y = x + \$622.7\ billion$

<em>Hence, the defense budget is x + $622.7 billion</em>

8 0

3 years ago

What is the volume of the right prism?

grigory [225]

V = 1/2B*H*L
V = 12*35*40/2
V= 16,800/2
V= 8,400 $in^{3}$

The volume of the right prism is B) 8,400 $in^{3}$

7 0

4 years ago

Read 2 more answers

The movement of the progress bar may be uneven because questions can be worth more or less (including

gogolik [260]

The answer is
0 4x=-9

8 0

2 years ago

WILL GIVE BRAINLY PLEASE HELP!!!!A rectangle has a length that is 5 inches greater than its width, and its area is 104 square in

Fiesta28 [93]

Answer: x2 + 5x – 104 = 0

Step-by-step explanation:

Distribute the x into the x + 5 to make it x2 + 5x
Subtract 104 from the other side to set the equation equal to zero
Final answer is x2 + 5x – 104 = 0

7 0

4 years ago

Read 2 more answers

In an arithmetic sequence, the sum of the 3rd and 8th term is 1. Given that the sum of the first seven terms is 35, determine th

Ann [662]

Answer:

<h3> first term: <u>a₁ = 14</u></h3><h3> the common difference: <u>d = -3</u></h3>

Step-by-step explanation:

The sum of the 3rd and 8th term is:

$a_3+a_8=1\\\\a_1+2d+a_1+7d=1\\\\\underline{2a_1+9d=1}$

The sum of the first seven terms is 35:

$S_7=35\\\\\dfrac{a_1+a_7}2\cdot7=35\\{}\qquad\quad^{\div7\qquad\div7}\\ \dfrac{a_1+a_1+d}2=5\\{}\qquad\qquad^{\cdot2\qquad\cdot2}\\2a_1+6d=10\\{}\qquad\ ^{\div2\qquad\div2}\\a_1+3d=5\\{}\quad\ ^{-3d\quad\ -3d}\\a_1=5-3d$

$2a_1+9d=1\\\\2(5-3d)+9d=1\\\\10-6d+9d=1\\{}\qquad\qquad^{-10\quad-10}\\{}\qquad3d=-9\\{}\qquad^{\div3\qquad\div3}\\{}\qquad d=-3\\\\\\a_1=5-3(-3)=5+9=14$

4 0

3 years ago