Explanation:
The history of Ottoman–Safavid relations (Persian: روابط عثمانی و صفوی) started with the establishment of Safavid dynasty in Persia (Iran) in the early 16th century. The initial Ottoman–Safavid conflict culminated in the Battle of Chaldiran in 1514, and was followed by a century of border confrontation. In 1639, Safavid Persia and Ottoman Empire signed the Treaty of Zuhab which recognized Iraq in Ottoman control, and decisively parted the Caucasus in two between the two empires. For most of it, the Zuhab treaty was a consolidation of the Peace of Amasya of about a century earlier.[1]
Persian and Ottoman Empire in 1661
Until the 18th century, the struggle between the Safavid version of Shia Islam and the Ottoman Turkish version of Sunni Islam had continued to remain an important dimension of the combative relationships between the two major empires.[2] In the early 18th century, Persian–Ottoman peace negotiations introduced a new concept of inter-Muslim relations whereby sovereign states could co-exist as autonomous parts of the Islamic world community.[3] Although the further relations were guided by the mutual fear of weakness and distrust, it wasn't until 1847 when Qajar Persia and Ottoman Empire reached a substantial peace Treaty of Erzurum, starting a century of peace,[2] after centuries of rivalry.
Answer:
There are three vertices of a rectangle, namely: A (−4,5), B (−4,2), C (3,2). This question forms part of Coordinate Geometry.
let the fourth vertex be D(a,b)
in rectangle mid points of the diagonals are same
mid point of BD = mid point of AC
[(a+7)/2,(b+4)/2] = [(4+13)/2,(1-2)/2] = (17/2,-1/2)
(a+7)/2 = 17/2 and (b+4)/2 = -1/2
a+7 = 17, and b+4 = -1
a = 17-7 =10, and b = -1-4 = -5
fourth vertex D is (10,-5)
Explanation:
It is C I think. Lebrian conquerors starved residents......
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