3 years ago

Six times the difference of a number and 4 is no more than 10.

1 answer:

klio [65]3 years ago

7 0

Answer:

nnnnnnnnnnnnnnnnnnnnnnnnn

Step-by-step explanation:

You might be interested in

MrMuchimi

Answers:
1. X= 0
2. X= 0
3. X=3

You can use this method to solve them step by step, hope it will help!

8 0

3 years ago

Alex17521 [72]

Solution:

$\sqrt{4x + 13} = x + 2$

$= > ( \sqrt{4x + 13} ) ^{2} = (x + 2) ^{2}$

Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

$= > 4x + 13 = {(x)}^{2} + 2 \times x \times 2 + (2) ^{2} \\ = > 4x + 13 = {x}^{2} + 4x + 4$

$= > 4x - 4x + 13 - 4 = {x}^{2} \\$

$= > {x}^{2} = 9 \\ = > x = \sqrt{9} \\ = > x = ±3$

Answer:

x = ± 3

Hope you could understand.

If you have any query, feel free to ask.

3 0

2 years ago

bixtya [17]

A is the correct answer to this question because AC and BC differ because the B must be changed to an A.

4 0

3 years ago

Nana76 [90]

11*11 is 121 so if you round one of this 11’s up to 11.364 you get just over 125

7 0

3 years ago

djyliett [7]

X=1

Mark brainliest please

Hope this helps you

7 0

2 years ago