Adam is taking a multiple choice test. His grade is given by the

Kay [80]

A. Slope is defined by rise/run. It looks like the points where it intersects the axes are at (0, 6) and (2, 0)
Basically you take (y-y1)/(x-x1), which in this case could be (6-0)/(0-2), which is -3.
b. The perpendicular slope would be the negative inverse of that.
The inverse of 3 is 1/3, so the negative inverse of -3 would also be 1/3.
c. The parallel slope is the same as the original slope.
d. Plug these points in for y=mx+b.
2=(1/3)(-1)+b
2=-1/3+b
b=7/3. (that's 2 and 1/3).
The equation for that line would be y=(1/3)x+(7/3)
e. The y intercept is found when x=0. But it's also the b in the y=mx+b equation, so the y intercept is (0, 7/3).

In case that's hard to read:
a. Slope = -3
b. Perpendicular Slope = 1/3
c. Parallel Slope = -3
d. y=(1/3)x+(7/3)
e. Y intercept = (0,, 7/3)

Hope that helps!

5 0

3 years ago

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Can anyone help me with this it’s question 2 help please

likoan [24]

Answer: 2x³ + 2x² + 36

Working:

= (2x + 6) × (x² - 2x + 6)

= 2x³ - 4x² + 12x + 6x² - 12x + 36

= 2x³ -4x² + 6x² +12x -12x +36

= 2x³ + 2x² + 36

Answered by Gauthmath must click thanks and mark brainliest

3 0

3 years ago

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the volume of a cylinder is 54 Pi centimeters to the third if the radius is 3 cm what is the height of the cylinder

padilas [110]

The height of the cylinder is 6 cm.

If the volume of the cylinder is 54π cm³, and we know the radius, we can use the formula for the volume of a cylinder to figure out the length of the height.

V = πr²h

Substitute

54π = 9hπ

Divide each side by π
54 = 9h

Get h by itself

h = 6, which means that the height of the cylinder is 6 cm.

6 0

3 years ago

Use deductive reasoning to show that P=R

qaws [65]

Answer:

∠P ≅ ∠R

Step-by-step explanation:

We can see here two triangles , ∆ PQS and ∆ RQS.

To Prove :-

∠P ≅ ∠R

We can prove the given two triangles congruent then we can easily prove it out.

In ∆ PQS and ∆ RQS

PQ = QR ( given )
QS = QS ( common)
∠PQS = ∠ RQS .

Therefore by SAS congruence condition , both triangles are congruent .

Hence ,

∠P ≅ ∠R ( by corresponding parts of congruent ∆s)

<h3>Hence Proved ! </h3>

6 0

3 years ago

FURTHER MATHEMATICS Use determinants to solve the systems of equation:

maw [93]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}2x+1y+2z&=&13\\1x+1y-2z&=&8\\1x+2y+1z&=&11\\\end{array}\right.\\\\\\\Delta=\left| \begin{array}{ccc}2&1&2\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\1&1&-2\\1&2&1\end{array}\right| =2*\left| \begin{array}{ccc}1&\frac{1}{2}&1\\0&\frac{1}{2}&-3\\0&1&3\end{array}\right| =2*(\frac{3}{2}+3)=9\\\\$

$\Delta_1=\left| \begin{array}{ccc}13&1&2\\8&1&-2\\11&2&1\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\8&1&-2\\\frac{11}{2}& 1&\frac{1}{2}\end{array}\right| =2*\left| \begin{array}{ccc}13&1&2\\-5&0&-4\\\frac{-5}{2}& 0&\frac{5}{2}\end{array}\right| \\\\=2*(-1)*(\frac{-25}{2}-\frac{20}{2}) =45\\$

$\Delta_2=\left| \begin{array}{ccc}2&13&2\\1&8&-2\\1&11&1\end{array}\right| \\\\\\=\left| \begin{array}{ccc}3&21&0\\3&30&0\\1&11&1\end{array}\right| \\\\\\=1*(90-63) =27\\$

$\Delta_3=\left| \begin{array}{ccc}2&1&13\\1&1&8\\1&2&11\end{array}\right| \\\\\\=\left| \begin{array}{ccc}0&-1&-3\\0&-1&-3\\1&2&11\end{array}\right| \\\\\\=0\\$

$\left\{\begin{array}{ccc}x=\dfrac{\Delta_1}{\Delta}=\dfrac{45}{9}=5\\\\y=\dfrac{\Delta_2}{\Delta}=\dfrac{27}{9}=3\\\\z=\dfrac{\Delta_3}{\Delta}=\dfrac{0}{9}=0\\\end{array}\right.$

8 0

3 years ago