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N76 [4]
3 years ago
15

Find the range of f in given ordered pair f(X)=8x-9,D={4,5,6}. plz help fastttt​

Mathematics
1 answer:
docker41 [41]3 years ago
5 0

Answer:

Hello! I would really like to help

but it seems this is out of my range!

I'm really sorry but all I can do is recommend

tutorials that will help with this question:

<u>https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:functions/x2f8bb11595b61c86:introduction-to-the-domain-and-range-of-a-function/v/range-of-a-function</u>

<u />

<u>https://www.khanacademy.org/math/algebra-home/alg-functions/alg-determining-the-range-of-a-function/v/domain-and-range-of-a-function-given-a-formula</u>

Step-by-step explanation:

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The ratio of the heights of two similar pyramids is 3:2. The volume of the larger pyramid is 135 cm3. What is the volume of the
gladu [14]
l-larger\\s-smaller\\\\\dfrac{h_l}{h_s}=\dfrac{3}{2}\to\dfrac{V_l}{V_s}=\left(\dfrac{3}{2}\right)^3\\\\V_l=135\ cm^3.\\subtitute\\\\\dfrac{135}{V_s}=\dfrac{27}{8}\ \ \ \ |cross\ multiply\\\\27V_s=135\cdot8\\\\27V_s=1080\ \ \ |divide\ both\ sides\ by\ 27\\\\\boxed{V_s=40\ (cm^3)}
3 0
3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
given the equation y-5=5x determine whether the points (2,12) and (-2,-5) are a solution on the graph
Flura [38]
(x,y)
sub points to see if we get true statemtn

(2,12)
x=2 and y=12

12-5=5(2)
7=10
false
no, (2,12) is not a point


(-2,-5)
x=-2
y=-5

-5-5=5(-2)
-10=-10
true
(-2,-5) is a soltuion

(-2,-5) is the only solution given that works
6 0
3 years ago
Find the pattern: 1, 1/4, 1/9, 1/16, 1/25
alexandr1967 [171]
The sequence is not geometric or arithmetic because there is no common difference or common ratio between each term.
Not a Geometric or Arithmetic Sequence
8 0
3 years ago
Y= x + 2<br> y= x + 6<br> How many solutions
Alona [7]

there \: is \: not \: any \: solutin \: for \: it \\ x + 2 = x + 6 \\ 2 = 6 \: is \: wrong

7 0
3 years ago
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