Question

Help?!?!??!!?!?????!​

Answer 1

Answer:

$n=10$

Step-by-step explanation:

$\frac{4^8}{(4^2)^-^3}\ / 4^4=4^n$

Simplify, remember, an exponent raised to the power of another exponent is equal to the product of the two exponents,

$\frac{4^8}{(4^2)^-^3}\ / 4^4=4^n$

$\frac{4^8}{4^-^6}\ / 4^4=4^n$

Now bring the term in the denominator (number under the fraction bar) to the numerator (number over the fraction bar). This can be done by multiplying the exponent of the denominator by (-1).

$\frac{4^8}{4^-^6}\ / 4^4=4^n$

$4^8(4^(^-^1^)^(^-^6^))\ / 4^4=4^n$

Simplify,

$4^8(4^6)\ / 4^4=4^n$

Remember, multiplying two numbers of the same base is the same as adding their exponents, apply this property here,

$4^8(4^6)\ / 4^4=4^n$

$4^1^4\ / 4^4=4^n$

Dividing two numbers of the same base is the same as subtraction their exponents,

$4^1^4\ / 4^4=4^n$

$4^1^0=4^n$

Thus, the following statement can be made,

$4^1^0=4^n$

$n=10$