Square root of 289 = +17 and -17
Answer:
solution:-We know that for any two finite sets A and B, n(A∪B)=n(A)+n(B)−n(A∩B).
Here, it is given that n(A)=20,n(B)=30 and n(A∪B)=40, therefore,
n(A∪B)=n(A)+n(B)−n(A∩B)
⇒40=20+30−n(A∩B)
⇒40=50−n(A∩B)
⇒n(A∩B)=50−40
⇒n(A∩B)=10
Hence, n(A∩B)=10
Step-by-step explanation:
hope it helps you friend ☺️
10 I think..I might be wrong
Answer:
The diagram reprents the 3 sets and the universal set . The shaded portion clearly can be seen as :
Shaded region = 
Try to understand some what complex
The probability of flipping 1 head when flipping 3 coins is 3/8.
Hope I helped!
