The sum if the geometric sequence given by:
an=-2(3)^(n-1)
will be:
when:
n=1
an=-2
when n=2
a2=-6
when n=3
a3=-18
when n=4
a4=-54
when n=5
a5=-162
when n=6
a6=-486
when n=7
a7=-1458
when n=8
a8=-4374
thus the summation of the term will be:
Sn=(-4374+-1458+-486+-162+-54+-18+-6+-2)
Sn=-6560
the answer is -6560
Answer:
3
Step-by-step explanation:
It should be 3 because when you look at it divide them all and each one gives you 3. If it's not then sorry.
Answer:
Organisms that break down dead or decaying organisms
Step-by-step explanation:
Hope this helps :b
Answer:
5 & 1
Step-by-step explanation:
We can use the quadratic formula to solve this:
Quadratic Formula = 
So we will have 2 answers (roots).
a is the coefficient of x^2 (2)
b is the coefficient of x (-12)
c is the constant (10)
Now, substituting, we get:
x = 
Hence the roots are 5 & 1
Answer:
a(n) = 13 - 2n
Step-by-step explanation:
The explicit formula variables are a(n) = a(1) + d (n - 1). The a(1) is your number you started out with, and the d is the common difference. From the recursive formula example, you see that your first number is 11 and your difference is -2.
1. Plug the numbers into the equation : a(n) = 11 - 2 (n - 1)
2. Distribute: a(n) = 11 - 2n + 2
3. Add like terms: a(n) = 13 - 2n
If you want to double check, you can plug 1 into n and see if you get 11. I did this, and I did so it should be correct. Hope this made sense! Have a great day :)