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Marta_Voda [28]
3 years ago
6

40 dogs and parrots in total (dogs + parrots = 40 in total) theres 130 legs, how much dog and parrots are there (need steps)​

Mathematics
2 answers:
34kurt3 years ago
8 0

Answer:

Step-by-step explanation:

To solve this, we need to list some equations. Letting variable d stand for dogs and p stand for parrots, we have:

d+p=40 (The number of dogs plus the number of parrots equals 40)

4d+2p=130 (Each dog has 4 legs and each parrot has 2 legs and they have 130 legs in total)

With this system of equations, we can quickly solve it for d and p.

Subtract:

 4d+2p=130

- d+p=40

_________

3d+p=90,

p=90-3d

Substitution:

d+(90-3d)=40

90-2d=40

-2d=-50

d=25

Substitution to get p:

p+25=40

p=15

There you have it! There are 25 dogs and 15 parrots. To check our work,

25+15=40

4(25)+2(15)=100+30=130

I hope this helped! :)

charle [14.2K]3 years ago
4 0

Answer: There are 32 dogs and 1 Parrot

Step-by-step explanation: I had a question like this in a math class. What you first do is to recognize that- parrots have 2 legs and dogs have 4. We can do 130/2 = 65 and 130/4= 32.5. Now we know that if there was only one animal, there would be 65 parrots, and 32 dogs- one with half of the legs. Since there is a .5 for the dogs, if we put in one parrot, it would mean that there is exactly 130.

(32 x 4)+(2x1) = 130.  There are 32 dogs and 1 Parrot. I hope this answer is ✅ and helps, i just joined the community and this is the first person I answered. Good Luck!!

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1) Mean of the set of data: 29.88

2) Mean absolute deviation: 10.13

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Step-by-step explanation:

1)

The mean of a set of data it is calculated as

\bar x = \frac{1}{N}\sum x_i

where

N is the number of data in the set

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For the set of data in this problem, we have:

x_i =[28, 45, 12, 34, 36, 45, 19, 20]

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N = 8

Therefore, we can calculate the mean:

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2)

The mean absolute deviation of a set of data is given by

\delta = \frac{1}{N}\sum |x_i-\bar x|

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x_i are the single values

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x_i =[28, 45, 12, 34, 36, 45, 19, 20]

The mean, calculated in part 1), is

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\delta = \frac{1}{8}(|28-29.88|+|45-29.88|+|12-29.88|+|34-29.88|+|36-29.88|+|45-29.88|+|19-29.88|+|20-29.88|)=\frac{81}{8}=10.13

3)

The mean of a dataset is the sum of the single values of the dataset divided by the number of values. The mean represents the value \bar x for which, if the dataset would have N values all equal to \bar x, the sum of the values of the dataset would be the same as the sum of the actual values.

The mean absolute deviation for a set of data represents the average of the absolute deviations of the single points from the mean of the dataset. This quantity gives a measure of the "dispersion" of the points around the mean: in fact, the larger the mean absolute deviation is, the more the points are "spread" around the mean of the dataset. Instead, if the mean absolute deviation is small, it means that the points are closer to the mean value.

Learn more about mean and spread of a distribution:

brainly.com/question/6073431

brainly.com/question/8799684

brainly.com/question/4625002

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