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sweet-ann [11.9K]

2 years ago

7

yesterday the temperature was 1 degree farenheit. today the temperature is 0 degree farhenheit. what is the change in tempeature

from yesterday to today

1 answer:

vesna_86 [32]2 years ago

7 0

Answer:

It is one degrees colder

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You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig

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Answer:no

Step-by-step explanation:

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3 years ago

A rectangle has a height of 3p^2+13p

frozen [14]

Answer:

-5p+7p^3

Step-by-step explanation: A rectangle has a height of 3p^2+13p

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2 years ago

Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2

ankoles [38]

Option C:

$2 g^{3}-5 g^{2}+6$

Solution:

Given expression:

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

To find which expression is equal to the given expression.

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

Expand the term $-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12$

$$=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}$

Arrange the like terms together.

$$=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}$

$$=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}$

Factor the numerator $2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)$

$$=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}$

Cancel the common factor g + 2, we get

$=2 g^{3}-5 g^{2}+6$

Hence option C is the correct answer.

8 0

2 years ago

Read 2 more answers

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Margarita [4]

Answer:

Step-by-step explanation:

$g(x)=\cos^{-1} (\frac{x}{2})\\g'(x)= \frac{- 1}{\sqrt{1-(\frac{x}{2})^2}}*\frac{1}{2} \\=\frac{-1}{\sqrt{4-x^2} }$

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3 years ago

Find the center and radius of (x + 8)2 + (y + 4)2 = 49.

Aleksandr-060686 [28]

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3 years ago