1. y<span> ≤ 4x/3+5
2. y</span><span>< 6x/4+3</span>
Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
<h3>How do we verify if a sequence converges of diverges?</h3>
Suppose an infinity sequence defined by:

Then we have to calculate the following limit:

If the <u>limit goes to infinity</u>, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:

Hence the limit is:

Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at brainly.com/question/6635869
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Answer:
$( 51x^2 + x + 29).
Step-by-step explanation:
Amount she had left = original amount - amount spent on the gloves
= 62x^2 + x - 4 - (11x^2 - 33) (note we place the amount spent on gloves in parentheses because we have to subtract the whole amount)
Now we distribute the negative over the parentheses:
= 62x^2 + x - 4 - 11x^2 + 33 ( note - 33 becomes -33*-1 = +33)
Now simplifying like terms:
= 51x^2 + x + 29 (answer).
Answer:
5 hours
Step-by-step explanation:
If shes going 59mph and the total trip is 295mph
then you would divid 295 by 59 and get 5
Divide the numerator and denominator by their gcf (25)
75/25= 3
100/25= 4
Final answer: 3/4