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3 years ago

This is my test question Round 1.391 to the nearest hundredth and I’m have a hard time I don’t understand I need the answer!!!

Mathematics

2 answers:

viva [34]3 years ago

5 0

Answer:

1.39

Step-by-step explanation:

nearest hundredth is 9

therefore 1.39 ig

sergiy2304 [10]3 years ago

3 0

Answer:

1.39

Step-by-step explanation:

0.090 is the hundreth. If the number in the thousandths spot is less than 5, which it is, you round back to 0.090

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Solve for this equation:<br> x(x+3)(x+3)=0

Marta_Voda [28]

Answer:

x^3+6x^2+9x

if you are trying to find the original function

if not, and you are trying to find the zeros is

x=-3

x=0

Step-by-step explanation:

multiply x(x+3)

x^2+3x

then multiply that by x+3 and that should give you the answer

6 0

2 years ago

Read 2 more answers

How many defective telephones

zhenek [66]

Answer:

Option 3: 300 phones

Step-by-step explanation:

Given

Phone produces each day: 1000

Number of phones that were checked = 30

Defective phones = 9

So the probability of defective phones will be calculated by dividing the number of defective phones by total number of phones checked.

So, the probability of defective phones

= 9/30

= 0.3 or 30%

So, from 1000 phones the defective phones will be:

1000*0.3

= 300 Phones ..

5 0

3 years ago

1/20 in dicimal please help

KonstantinChe [14]

0.05 is the answer for your question.

8 0

4 years ago

A librarian has weekends off and has 10 paid vacation days per year, including holidays that fall on weekdays. If his salary is

Free_Kalibri [48]

5*52=260-10=250 32500/250=130

8 0

3 years ago

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Find the standard deviation of 21, 31, 26, 24, 28, 26

Vesnalui [34]

Given the dataset

$x = \{21,\ 31,\ 26,\ 24,\ 28,\ 26\}$

We start by computing the average:

$\overline{x} = \dfrac{21+31+26+24+28+26}{6}=\dfrac{156}{6}=26$

We compute the difference bewteen each element and the average:

$x-\overline{x} = \{-6,\ 5,\ 0,\ -2,\ 2,\ 0\}$

We square those differences:

$(x-\overline{x})^2 = \{36,\ 25,\ 0,\ 4,\ 4,\ 0\}$

And take the average of those squared differences: we sum them

$\displaystyle \sum_{i=1}^n (x-\overline{x})^2=36+25+4+4+0+0=69$

And we divide by the number of elements:

$\displaystyle \sigma^2=\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n} = \dfrac{69}{6} = 11.5$

Finally, we take the square root of this quantity and we have the standard deviation:

$\displaystyle\sigma = \sqrt{\dfrac{\sum_{i=1}^n (x-\overline{x})^2}{n}} = \sqrt{11.5}\approx 3.39$

8 0

3 years ago