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jeyben [28]
3 years ago
10

!20 Point! Please help me find the surface area!

Mathematics
2 answers:
Vika [28.1K]3 years ago
7 0

Answer:

The base is 12 the height is 8.

Using the formula of finding the area of a triangle: BH x 1/2

8 x 12 x 1/2 = 48 Area of one triangle.

Since there are 4 equilateral triangles we multiply the area of one triangle 4 times since they are all equal.

48 x 4 = 192 in2 is your surface area

(haven't done this in quite a while so make sure to check other answers for more reassurance)

Free_Kalibri [48]3 years ago
3 0

PLEASE, forgive me but I answered this and hopefully what I see is correct. I’m really sorry if this weren’t the real measurements!

Answer:

192 square inches

Step-by-step explanation:

Surface area questions often include the net for easy answering. All you do is just find the area of each face and add them all up:

As you can see, all triangles in this net of a pyramid are the same, so once we find the area of one triangle, we’ll just multiply by 4:

FIND AREA OF ONE TRIANGLE (1/2 x b x h)

1/2 x 8 x 12 = 48 square inches

MULTIPLY BY 4 for SURFACE AREA:

48 x 4 = 192

so the SA is 192 square inches!

brainliest?

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Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
I need help finding this angle! I will mark you if you help!
Lady_Fox [76]

It's an acute angle because it's smaller than 90 degrees and isn't a straight line.

4 0
3 years ago
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What is the percent of 72 out of 96
marin [14]
72/96 * 100= 75% so the answer is 75%
4 0
3 years ago
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18) A company is planning to manufacture a new blender. After conducting extensive
zhenek [66]

Answer:

  R(x) = -0.05x^2 +80x

Step-by-step explanation:

Given the two points (x, p), the equation for the price associated with a given demand quantity can be written using the 2-point form:

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  p = -0.05x +80 . . . . simplify

Then the revenue equation is ...

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7 0
3 years ago
The sum of two numbers is 67. the smaller number is 3 less than the larger number. what are the two numbers?
V125BC [204]
Let the larger number be x
The smaller number would be x-3 

(x-3)+x=67 
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2x=67-3 
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x=64/2 
x=32 

Therefore the larger number is 32 and the smaller is (32)-3= 29 

Hope I helped :) 
7 0
3 years ago
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