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Alenkasestr [34]
3 years ago
14

*HELP*

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

96 dollars and 50 cents

Step-by-step explanation:

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They are arranged randomly because manual typewriters tended to jam if the user typed too fast - therefore the arrangement was i
solmaris [256]

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Huh

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Huh......................

8 0
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A group of 4 people are sharing jellybeans. Each person wants 6 jellybeans and each box has 8 jellybeans.
loris [4]

Answer:

<u>3</u>

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4 x 6 = 24

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2 years ago
PLEASE HELP! I'm struggling on questions like this one. If you can please help on other questions but that's up to you! I will g
Jobisdone [24]

Answer: y=x-4

Step-by-step explanation:

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3 years ago
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Solve for y in this equation<br> 6( y-1) -9=-5(-3y+5) -3y
saul85 [17]
6(y-1)-9=-5(-3y+5)-3y
6y-6-9=15y-25-3y
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18y=-25
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or -1 19/50
8 0
4 years ago
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find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}
inn [45]
Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2  and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2      and  x" = [10 - √64]/2

x' = (10+12)/2    and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity


6 0
3 years ago
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