For the answer to the question above, I'll show my solution for the answer below.
Area A = pi r^2
<span>The rate of change of area = d A/ d t = 2 pi r d r/d t </span>
<span>r= 2t, d r = 2 d t </span>
<span>This gives </span>
<span>d A/ d t = 2 pi 2t 2 d t = 8 pi t dt </span>
<span>Integrate it </span>
<span>A= 4 pi t^2. </span>
<span>After t=5, the area will be 100* 3.14 square= 314 square units.</span>
Answer:
153
Step-by-step explanation:
If the table adds up to 20 and opened toe counts for 45% of the total. then 45% of 340 is 153 !
If a line is parallel to another, the slopes of both lines are the same. So for this problem, you can infer that the slope of the line you're trying to find is 3.
To find the actual equation of the line, you can use the given coordinates and plug them into the point slope form:
y - y1 = m(x - x1)
plug the given y coordinate into y1 and the given x coordinate into x1. m is the slope, so plug in 3 for m.
y - 1 = 3(x +2) Use distributive property for right side of equation
y - 1 = 3x + 6 add 1 to both sides to cancel -1 on left side of equation and isolate y
Equation of line: y = 3x + 7
The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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