The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
Step-by-step explanation:
Step-by-step explanation:
1.Right
2.Left
3.Bottom Middle
If the problem is 6r•s•4rt•10rst, then the answer is 240•r^3•s^2•t^2.
Answer:1.72Gal
Step-by-step explanation:1 Gal is 3.785 L. 6.5 / 3.785 = 1.72
Answer:
The two lines intersect (intersecting lines) at point (1, 2) on a graph
Step-by-step explanation:
