(2x-a) (2x+a) solve this
2 answers:
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Answer is a
*The correct answer is IJ = JK
•explanation:
Given:
AB is the perpendicular bisector of
IK. ⇒ AB divides the line segment IK in two equal parts i.e. IJ = JK and the angle formed at the point of intersection J is 90° ⇒ ∠AJI = 90°. In ΔAIJ, By angle sum property of a triangle ∠AJI + ∠AIJ + ∠IAJ = 180° ( But ∠AJI = 90° ) ∠AIJ + ∠IAJ = 90° ⇒ ∠IAJ < 90° So, ∠IAJ is not a right angle. Its not given IK is a perpendicular bisector so AJ = BJ need NOT be true. As A does not lie on the line IK so A can not be the mid point of IK.
•Hence, we conclude the correct statement is IJ = JK
*The correct answer is IJ = JK
•explanation:
Given:
AB is the perpendicular bisector of
IK. ⇒ AB divides the line segment IK in two equal parts i.e. IJ = JK and the angle formed at the point of intersection J is 90° ⇒ ∠AJI = 90°. In ΔAIJ, By angle sum property of a triangle ∠AJI + ∠AIJ + ∠IAJ = 180° ( But ∠AJI = 90° ) ∠AIJ + ∠IAJ = 90° ⇒ ∠IAJ < 90° So, ∠IAJ is not a right angle. Its not given IK is a perpendicular bisector so AJ = BJ need NOT be true. As A does not lie on the line IK so A can not be the mid point of IK.
•Hence, we conclude the correct statement is IJ = JK