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3 years ago

Prove that the bisector of the vertical angle of isosceles triangle is the perpendicular bisector of the base

Mathematics

1 answer:

julia-pushkina [17]3 years ago

7 0

Answer:

We will take two angles and name them 'x'

And their sum must equal 180

So,

x + x = 180

2x = 180

x = 180/90

x = 90

Hence, it is proved that the bisector of the vertical angle of isosceles triangle is the perpendicular bisector of the base.

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-Dominant- [34]

By iteratively substituting, we have

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and the pattern continues down to the first term $a_1=0$ ,

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$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

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Step-by-step explanation:

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