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3 years ago

Can someone please help me

Mathematics

1 answer:

Genrish500 [490]3 years ago

8 0

Answer:

Step-by-step explanation:

come on ! you can literally see that in the chart.

how many parts of the gray 3/8 are covered by the gray 1/4 ?

2 parts = 2/8 are clearly covered by 1/4.

2/8 is what part of 3/8 ?

it is the same question as "2 is what part of 3" ?

is 2 a quarter (1/4) of 3 ? no, 1/4×3 = 3/4 and not 2.

is 2 one third (1/3) of 3 ? no, 1/3 of 3 = 1/3×3 = 1 and not 2.

is 2 two thirds (2/3) of 3 ? ah, 2/3 × 3 = 2. that is correct !

is 2 three quarters (3/4) of 3 ? no, 3/4×3 = 9/4 and not 2.

once you have the same denominator, you can easily compare the numerators and ignore the denominators for such problems.

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Express cos I as a fraction in simplest terms.

Serga [27]

Answer:

Solution given

Cos I=adjacent/hypotenuse=16/34

8/17 is a required answer.

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3 years ago

Which series of transformations occurred to move the blue figure to the red figure? a translation and then a reflection

Alborosie

Answer:

A translation and then a reflection

Step-by-step explanation:

A translation of 5 to the left, and then a a reflection across the x axis.

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3 years ago

What is the measure of line CD. explain

Karo-lina-s [1.5K]

So the answer will be 15-19 one of those numbers so 15 16 17 18 or 19

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%20%5Csqrt%7Bx%7D%20%20%2B%20%20%5Csqrt%5B5%5D%7Bx%7D%20" id="

lesya [120]

Answer:

$3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }$

Step-by-step explanation:

Just to make it easier to see, $\sqrt{x} = x^{\frac{1}{2} }$ and $\sqrt[5]{x} = x^{\frac{1}{5} }$ This way we could more easily use the power rule of derivatives.

So if f(x) = $x^{2} +x^{\frac{1}{2} } +x^{\frac{1}{5} }$ then f'(x) will be as follows.

f'(x) = $x^{1} +\frac{1}{2} x^{-\frac{1}{2} } +\frac{1}{5} x^{-\frac{4}{5} } = x +\frac{1}{2x^{\frac{1}{2} }} +\frac{1}{ 5x^{\frac{4}{5} }} = x +\frac{1}{2\sqrt{x}} +\frac{1}{ 5\sqrt[5]{x^4} }$

to find f'(3) just plug 3 into f'(x) so $3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }$

8 0

3 years ago

Help? Please? I really suck at geometry

Maslowich

Answer:

x = 14

y = 4

Explanation:

Ok so, just from looking at the two triangles i can tell they're congruent right triangles. I used different colors to show which sides of the triangle correspond and are equal to each other in my attatched photo.

So the side thats equal to x is the same length as the side that's equal to y+10 on the other triangle.

So we can write the equation x = y + 10.

Using this same method, the side that's equal to x + 2 is the same length as the side that's equal to 4y on the other triangle.

So, we can write the equation 4y = x + 2.

Now we have the equations $\left \{ {{x=y+10} \atop {4y=x+2}} \right.$ you could rewrite to be in slope- intercept form so they're easier to graph. But a graphing calculator online would plot it just fine.

If you graph these two equations they'll intersect at the solution ( 14, 4 ). I'll include the graph in my images as well.

To check your answer, you can plug in x and y and see if the triangle sides end up being the same length. I did and it was correct.

8 0

3 years ago