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3 years ago

What is the length of segment AB?

Mathematics

1 answer:

8_murik_8 [283]3 years ago

8 0

Answer:

-1

Step-by-step explanation:

then the sum of the line come home x axis

-4+3=-1

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Could you take sometime to help me on this please?

mariarad [96]

ANSWER = -1

hi, take x = -1

$-1\leq -1 \ so \ x\leq -1 \\ \\\text{ BUT } x^3=-1 < -1 \text{ is wrong}$

Thanks

8 0

3 years ago

Read 2 more answers

What is the solution to the equation 3 + 4 sqr root 4y = 4?

lawyer [7]

Answer:

1/64

Step-by-step explanation:

Given the expression

3+4√4y = 4

4√4y = 4-3

4√4y = 1

√4y = 1/4

Square both sides

(√4y)²= (1/4)²

4y = 1/16

y = 1/16 * 1/4

y = 1/64

Hence the value of y is 1/64

6 0

3 years ago

Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel

timama [110]

Answer:

$\displaystyle A=\frac{1}{192}$

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

$P=4x+3y$

We know the total fencing is 1/2 miles long, thus

$\displaystyle 4x+3y=\frac{1}{2}$

Solving for x

$\displaystyle x=\frac{\frac{1}{2}-3y}{4}$

The total area of the pasture is

$A=x.y$

Substituting x

$\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y$

$\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}$

Differentiating with respect to y

$\displaystyle A'=\frac{\frac{1}{2}-6y}{4}$

Equate to 0

$\displaystyle \frac{\frac{1}{2}-6y}{4}=0$

Solving for y

$\displaystyle y=\frac{1}{12}$

And also

$\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}$

Compute the second derivative

$\displaystyle A''=-\frac{3}{2}.$

Since it's always negative, the point is a maximum

Thus, the maximum area is

$\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}$

6 0

3 years ago

The maximum weight allowed per car on The Twister carnival ride is 263 pounds. Your friend weighs 86 pounds. To be able to ride

Kazeer [188]

Your weight: x lb
Friend's wt.: 86 lb
Max wt. allowed: 263 lb

Then x + 86 ≤ 263, with x in lb. You could weigh a max. of 177 lb and still be able to go on this ride.

4 0

3 years ago

200 + 200m - 100 - 100m + 100

slava [35]

Answer:

200+100m

Step-by-step explanation:

Simplified by collecting like terms

5 0

2 years ago