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3 years ago

What is the length of segment AB?

Mathematics

1 answer:

8_murik_8 [283]3 years ago

8 0

Answer:

-1

Step-by-step explanation:

then the sum of the line come home x axis

-4+3=-1

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4x^2 - 35x - 99 / x^2 - 5x - 66 Simplify this expression and state any restrictions on the variable

arsen [322]

$\frac{4x^{2} - 35x - 99}{x^{2} - 5x - 66} = \frac{4x^2 - 44x + 9x - 99}{x^{2} - 11x + 6x - 66} = \frac{4x(x) - 4x(11) + 9(x) - 9(11)}{x(x) - x(11) + 6(x) - 6(11)} = \frac{4x(x - 11) + 9(x - 11)}{x(x - 11) + 6(x - 11)} = \frac{(4x + 9)(x - 11)}{(x + 6)(x - 11)} = \frac{4x + 9}{x + 6}$

6 0

3 years ago

Read 2 more answers

Suppose that the pH of soil samples taken from a certain geographic region is normally distributed with a mean pH of 7 and a sta

Otrada [13]

Answer:

a) P=0

b) P=1

c) P=0

d) X=7.1645

Step-by-step explanation:

We have the pH of soil for some region being normally distributed, with mean = 7 and standard deviation of 0.10.

a) What is the probability that the resulting pH is between 5.90 and 6.15?

We calculate the z-score for this 2 values, and then compute the probability.

$z_1=(X_1-\mu)/\sigma=(5.9-7.0)/0.1=-11\\\\z_2=(X_2-\mu)/\sigma=(6.15-7)/0.1=-8.5$

Then the probability is

$P(5.90$

b) What is the probability that the resulting pH exceeds 6.10?

We repeat the previous procedure.

$z=(6.10-7)/0.1=-9\\\\P(x>6.1)=P(z>-9)=1$

c) What is the probability that the resulting pH is at most 5.95?

$z=(5.95-7)/0.1=-10.5\\\\P(x$

d. What value will be exceeded by only 5% of all such pH values?

We have to calculate the value of pH for which only 5% is expected to be higher. This can be represented as P(X>x)=0.05.

In the standard normal distribution, it happens for a z=1.645.

$P(z>1.645)=0.05$

Then, we can calculate the pH as:

$x=\mu+z\sigma=7.0+1.645*0.1=7.0+0.1645=7.1645$

4 0

3 years ago

What is the nth term of the geometric sequence 4,8,16,32

sdas [7]

Answer: 64

Step-by-step explanation: 32x2, the pattern is it doubles

5 0

3 years ago

Read 2 more answers

Write the point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5)?

nevsk [136]

The point-slope form of the equation of the line through the given points through: (-3,-1) and (-2,5) is y + 1 = 6x + 18

Solution:

Given, two points are (-3, -1) and (-2, 5)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

The slope of line "m" is given as:

$\text { slope of line } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }$

Now, let us find the line equation using point slope form

$y-y_{1}=m\left(x-x_{1}\right)$

where m is slope

$\begin{array}{l}{\text { Then, line equation } \rightarrow y-(-1)=6(x-(-3))} \\\\ {\rightarrow y+1=6(x+3)} \\\\ {\rightarrow y+1=6 x+18}\end{array}$

Hence the point slope form is y + 1 = 6x + 18

7 0

3 years ago

Using the equation x= 12- 3y, complete the ordered pair (___,-5).

cupoosta [38]

27 because like 12-3time -5 which would be -15 and then with thte 12-(-15)=27 SO THE ANSWER IS 27

3 0

3 years ago