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3 years ago

Please help!! 25 points!!

Mathematics

1 answer:

Archy [21]3 years ago

5 0

9514 1404 393

Answer:

(a) a^4/(4b^2)

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)/(a^c) = a^(b-c)

a^-b = 1/a^b

Your expression simplifies as follows.

$\dfrac{3a^2b^{-4}}{12a^{-2}b^{-2}}=\dfrac{3}{12}\cdot\dfrac{a^{2-(-2)}}{b^{-2-(-4)}}=\boxed{\dfrac{a^4}{4b^2}}$

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Answer:

The answer is 10

Step-by-step explanation:

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3 years ago

The slope of a line passing through H (-2, 5) is -3/4. Which ordered pair represents a point on this line?

oksano4ka [1.4K]

Answer:
(6,-1)

Explanation:
The slope of the line can be calculated using the following formula:
slope = $\frac{y2-y1}{x2-x1}$

We are given that:
slope = -0.75
point (x1,y1) is (-2,5)

We will use each of the given points to calculate the corresponding slope, then compare the calculated slope with the given one.

For point (6,-1):
slope = $\frac{-1-5}{6--2}$ = -0.75 ........> accepted choice

For point (2,8):
slope = $\frac{8-5}{2--2}$ = 0.75 ........> rejected choice

For point (-5,1):
slope = $\frac{1-5}{-5--2}$ = 4/3 ........> rejected choice

For point (1,1):
slope = $\frac{1-5}{1--2}$ = -4/3 ........> rejected choice

Therefore, the first option is the only correct one.

Hope this helps :)

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3 years ago

Suppose a parabola has an axis of symmetry at x = -2, a minimum height at -6, and passes through the point (0, 10). Write the eq

lesantik [10]

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3 years ago

I need to find the ratio of the line

Tom [10]

-2 or -2/1 because the ratio is y over x and the line is going down 2 (-2) every time it goes to the right once (1)

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3 years ago

HELPPP ASAPPP DUE SOONN

Andru [333]

The friction force exerted on the 2400kg car is 9408 Newtons

<h3>What force will be exerted on the 2400kg car?</h3>

First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:

F = k*M

Where F is the force, M is the mass and k is the constant of proportionality.

We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:

6272N = k*1600kg

Solving for k we get:

k = (6272N)/(1600 kg) = 3.92 N/kg

Then the proportional relationship is:

F = (3.92 N/kg)*M

So if M = 2400kg, we have:

F = (3.92 N/kg)*2400kg = 9408 N

So the friction force exerted on the 2400kg car is 9408 Newtons

If you want to learn more about proportional realtions:

brainly.com/question/12242745

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3 years ago