F(x) = Square root of quantity x plus seven. ; g(x) = 8x - 11 Find f(g(x)). (1 point)

Mathematics

2 answers:

Rudik [331]3 years ago

7 0

$\\ \sf\longmapsto f(x)=\sqrt{x+7}$

$\\ \sf\longmapsto g(x)=8x-11$

g(x) will be put on the place of x

$\\ \sf\longmapsto f(g(x))=\sqrt{8x-11+7}$

$\\ \sf\longmapsto f(g(x))=\sqrt{8x-4}$

$\\ \sf\longmapsto f(g(x))=\sqrt{4(2x-1)}$

$\\ \sf\longmapsto f(g(x))=2\sqrt{2x-1}$

Ahat [919]3 years ago

6 0

Answer:

2 sqrt(2x-1)

Step-by-step explanation:

f(x) = sqrt(x+7)

g(x) = 8x-11

f(g(x))=

Place g(x) in for x in the function f(x)

f(g(x)) = sqrt( 8x-11 +7)

= sqrt( 8x -4)

Factor out 4

= sqrt( 4(2x-1)

= 2 sqrt(2x-1)

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4 0

4 years ago

Help on this please

eimsori [14]

Answer:

Opening: Opens upwards

Axis of Symmetry: -7/2

Vertex: (-7/2, -81/4)

X - intercepts: (1, 0) and (-8, 0)

Y - intercept: (0, -8)

Step-by-step explanation:

Opening: 'a' is greater than zero

Axis of Symmetry:

$\frac{-7}{2(1)} =\frac{-7}{2}$

Vertex:

$y= (\frac{-7}{2})^{2} +7(\frac{-7}{2}) -8\\y= (\frac{49}{4}) +(\frac{-49}{2}) -8\\y= \frac{49}{4} +\frac{-98}{4} -8\\y=\frac{-49}{4}-8\\y = \frac{-81}{4}$