All categories

3 years ago

Can some one help me answer this

Mathematics

1 answer:

lesya692 [45]3 years ago

3 0

7. √9

√9 is a rational number because √9 = 3 = 3/1.

8. No, there is no integer between -6 and -7.

9. π

π is an irrational number

You might be interested in

Find the interest rate if £6400 has a final value of £8334 in 3 years. Give your answer to 1 d.p

Mila [183]

Answer:

Step-by-step explanation:

6400(1+i)³=8334

(1+i)³=1.3021875

∛(1+i)³=∛(1.3021875)

1+i= 1.092

i= .092

I guess if you were to round to 1 decimal point it'd be .1

4 0

2 years ago

For a quantity that changes frequently from month to month, the best kind of graph is a pie chart.

lana66690 [7]

For a quantity that changes frequently from month to month, the best kind of graph is a pie chart.a true

3 0

3 years ago

Read 2 more answers

What is the perimeter of the shape below, given a = 5.66, b = 13.75, c = 6.76, d = 4.59

Marina86 [1]

Answer:

61.52

Step-by-step explanation:

5.66+ 13.75 + 6.76 + 4.59 + 5.66+ 6.76 + 13.75 +4.59

7 0

3 years ago

Read 2 more answers

Find the mean of the data.

Vladimir79 [104]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Help please! Will pick the Brainliest.<br> (sorry if it’s sideways)

KatRina [158]

$(x^2y^8)^\frac{2}{3}=x^{2\cdot\frac{2}{3}}y^{8\cdot\frac{2}{3}}=x^{\frac{4}{3}}y^{\frac{16}{3}}=x^{1\frac{1}{3}}y^{5\frac{1}{3}}=x^1x^\frac{1}{3}y^5y^\frac{1}{3}=xy^5\sqrt[3]{x}\sqrt[3]{y}=\boxed{xy^5\sqrt[3]{xy}}$

Answer B)

$\frac{1}{3}\left(\frac{2}{15}x-\frac{2}{3}\right)>x+\frac{1}{5}\quad|\cdot3\\\\\\\frac{2}{15}x-\frac{2}{3}>3x+\frac{3}{5}\quad|\cdot15\\\\\\2x-\frac{30}{3}>45x+\frac{45}{5}\\\\2x-10>45x+9\\\\-10-9>45x-2x\\\\-19>43x\quad|:43\\\\\boxed{x$

Answer B)

$\sqrt{14xy}\cdot\sqrt{12}\cdot\sqrt{30y}=\sqrt{14\cdot12\cdot30}\cdot\sqrt{xy^2}=\sqrt{2\cdot7\cdot3\cdot4\cdot2\cdot3\cdot5}\cdot\sqrt{xy^2}=\\\\=\sqrt{2^2\cdot3^2\cdot2^2\cdot5\cdot7}\cdot\sqrt{xy^2}=2\cdot3\cdot2\cdot\sqrt{35}\cdot y\cdot\sqrt{x}=\boxed{12y\sqrt{35x}}$

3 0

3 years ago