Answer:
The equations that represent the reflected function are
Step-by-step explanation:
The correct question in the attached figure
we have the function
we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore
The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)
An equivalent form will be
![f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B%28-1%29%28x%29%7D%3D5%5B%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-1%7D%29%5D%5E%7Bx%7D%3D5%285%29%5E%7Bx%7D)
therefore
The equations that represent the reflected function are
Answer:
Step-by-step explanation:
Let 
. We have that 
if and only if we can find scalars 
such that 
. This can be translated to the following equations:
1. 
2.
3. 
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for 
and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get
whose unique solutions are 
, but note that for this values, the third equation doesn't hold (3+2 = 5 
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get
whose unique solutions are 
. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.
Answer:
So first you have to do 12-2 since it's in parenthesis. It is 10. 5+4 is 9, and 9 times 10 is 90. 3 squared is 9, then you divide 90 by 9. The answer is 10.
Answer:
150
Step-by-step explanation:
300-150
Answer:
3y=x-1 OR y=⅓x-⅓
Step-by-step explanation:
Lets call the equation y=-3x+7 line l1
the other line passing through (4,1) l2
If two lines are perpendicular,then the product of their roots=-1
That is m(l1)×m(l2)=-1
Slope of l1=-3 therefore slope of l2=-1÷-3=⅓
Now that we have determined the slope of l2 we move on to find it's equation using the point-slope form
y-y1=m(x-x1)
y-1=⅓(x-4)
3y-3=x-4
3y=x-4+3
3y=x-1 OR y=⅓x-⅓
