Multiply. Write your answer in the simplest form. 3/8×3/7×4
2 answers:
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Okay so lets look at the equation given
this is the Pythagorean theorem, this equation holds true to all right angle triangles.
for the "a" and "b" terms must be the two shortest lengths and "c" must be the longest length.
why? because "c" represents the hypotenuse in this theorem and the hypotenuse is by definition the longest side of a right triangle.
(side note: always draw a picture, it helps a lot if you doodle a bit to get an idea of what you are working with)
we are given three lengths : 3 , 4, and 5 (im ignoring the measurements for now)
we can look at it two ways with a picture and through algebra
try to draw a right triangle with the given info. you'll see there are only two cases were this is possible the picture above is one case where this is not possible
now we can look at this algebraically
(but "a" and "b" can swap lengths)
now with the Pythagorean theorem we can see how this plays out
and heres with "a" and "b" lengths swapped
now here's a case when we let 5 , our longest length , become a leg and let one our shorter lengths take the place of "c"
obviously 34 does not equal 16
hope this helped you out
this is the Pythagorean theorem, this equation holds true to all right angle triangles.
for the "a" and "b" terms must be the two shortest lengths and "c" must be the longest length.
why? because "c" represents the hypotenuse in this theorem and the hypotenuse is by definition the longest side of a right triangle.
(side note: always draw a picture, it helps a lot if you doodle a bit to get an idea of what you are working with)
we are given three lengths : 3 , 4, and 5 (im ignoring the measurements for now)
we can look at it two ways with a picture and through algebra
try to draw a right triangle with the given info. you'll see there are only two cases were this is possible the picture above is one case where this is not possible
now we can look at this algebraically
(but "a" and "b" can swap lengths)
now with the Pythagorean theorem we can see how this plays out
and heres with "a" and "b" lengths swapped
now here's a case when we let 5 , our longest length , become a leg and let one our shorter lengths take the place of "c"
obviously 34 does not equal 16
hope this helped you out
The heights the balls hit a fence at 350 ft distance are 65 feet, 38 feet and 30 feet, respectively
<h3>Represent the distance-height relationship for each player’s ball as an equation, in a table and on a graph. </h3><u>Juan</u>
Juan's equation is given as:
h = -0.001d^2 + 0.5d + 2.5
h =
Set d to multiples of 50 from 0 to 400.
So, the table of values of Juan's function is:
d (ft) h(ft)
0 2.5
50 25
100 42.5
150 55
200 62.5
250 65
300 62.5
350 65
400 42.5
See attachment for the graph of Juan's function
<u>Mark</u>
A quadratic function is represented as:
h = ad^2 + bd + c
Using the values on the table of values, we have:
c = 3 -- the constant value
So, the equation becomes
h = ad^2 + bd + 3
Using the two other values on the table of values, we have:
23 = a(50)^2 + b(50) + 3
38 = a(100)^2 + b(100) + 3
Using a graphing tool, we have:
a = -0.001
b = 0.45
So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3
See attachment for Mark's graph.
<u>Barry</u>
From the graph, we have the table of values of Barry's function to be:
d (ft) h(ft)
0 2.5
50 21
100 35
150 44
200 48
250 46
300 41
350 30
400 14
450 0
Using a graphing tool, we have the quadratic function to be:
y = -0.001x^2 +0.4x +2.5
<h3><u>The shortest and the greatest distance before hitting the ground</u></h3>From the graphs, equations and tables, the distance travelled by the balls are:
Juan = 505 feet
Mark = 457 feet
Barry = 450 feet
This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.
<h3>The height the balls hit a fence at 350 ft distance</h3>To do this, we set d = 350
From the graphs, equations and tables, the height at 350 ft by the balls are:
Juan = 65 feet
Mark = 38 feet
Barry = 30 feet
The above represents the height the balls hit the fence
Read more about quadratic functions at:
#SPJ1
