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Effectus [21]
3 years ago
13

Solve: XXVI - IV. Show your answer in standard form. Standard Number 1 5 10 50 100 500 1,000 Roman Numeral 1 V x L lulolz A) 22

B) 20 C) 19​
Mathematics
2 answers:
Nezavi [6.7K]3 years ago
3 0

Answer:

22

Step-by-step explanation:

these i can do keep sendin em in

morpeh [17]3 years ago
3 0

Answer:

22

b/c XXVI - IV

(26 - 4 )

=22

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Please can someone help; this is not cheating btw.
Umnica [9.8K]

By determining the area of the square, we get x^{2} +4x = 3.

Step-by-step explanation:

Step 1:

The area of a square is given by squaring its side length.

The given squares side length is (x+2) cm.

The area of a square = a^{2} . Here a is the side length.

The area of the square is given as 7 cm².

Step 2:

Substituting the value of a in the equation, we get

7 = (x+2)^{2} = x^{2}  + 4x + 4.

Taking the x values on one side and the constants on the other side, we get

x^{2} +4x= 7-4 =3.

So x^{2} +4x = 3.

So it has been proved.

4 0
4 years ago
6
skad [1K]

Answer:

is there a pic u could show?

Step-by-step explanation:

4 0
3 years ago
I don’t really understand this
frozen [14]
Use a calculator and multiple
4 0
3 years ago
Luis has $550 saved for a car,and he saves an additional $50 per week. Kya has 810 saved for a trip, and she saves an additional
Debora [2.8K]
About 9 weeks. With Luis at 1000 and kya At 1008. Theirs no exact.

Graph into calc
Stat plot
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Then press 2nd and graph.
4 0
3 years ago
Which of the following accurately lists all of the discontinuities for the graph below?
Murljashka [212]

Answer:

jump discontinuity at x = 0; point discontinuities at x = –2 and x = 8

Step-by-step explanation:

From the graph we can see that there is a whole in the graph at x=-2.

This is referred to as a point discontinuity.

Similarly, there is point discontinuity at x=8.

We can see that both one sided limits at these points are equal but the function is not defined at these points.

At x=0, there is a jump discontinuity. Both one-sided limits exist but are not equal.

3 0
3 years ago
Read 2 more answers
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