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Romashka [77]
2 years ago
5

Find the odds:

Mathematics
1 answer:
gayaneshka [121]2 years ago
3 0

Answer:

6/23

Step-by-step explanation:

First, find the total number of marbles:

6 + 8 + 9

= 23

There are 6 red marbles out of the 23.

So, the odds of choosing one will be 6/23.

You might be interested in
the volume V of a gas at a constant temperature varies inversely with the pressure P. when the volume is 100 cubic inches the pr
fiasKO [112]

Answer:

The pressure is 20\ psi

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

In this problem we have

V*P=k

where

V is the volume of a gas at a constant temperature

P is the pressure

we have

For V=100\ in^{3},P=25\ psi

step 1

Find the value of k

substitute the values of V and P

100*25=k

k=2,500

The equation is equal to  V*P=2,500

step 2

Find the pressure when the volume is 125 cubic inches

For V=125\ in^{3}

substitute in the equation and solve for P

125*P=2,500

P=2,500/125=20\ psi

8 0
3 years ago
Simplify. -10m+2m^4-13m-20m^4
Ulleksa [173]
First one:

you can add -10m and -13m but you can't add -10m and 2m^4 becuase the powers aren't the same so

when adding the like terms
look at the:
powers, (x^3 adds with x^3)
placehloder letter (x adds with x and y adds with y and so on)

-10m+2m^4-13m-20m^4
powers: m^1 and M^4
placeholders: all m


add
-10m-13m+2m^4-20m^4
-23m-18m^4




second one:
when multiplying exponents, you add with like
so if you multipliy
x^2yz^3 times x^4y^2z^2 thne you would get x^6y^3z^5
when multiply with coeficients
2x^2yz^3 times 4x^4y^2z^2=8x^6y^3z^5
so using associative property a(bc)=(ab)c
2/3 times p^4 times y^3 times y^4 times s^5 times 6 times p^2 times s^3
group like terms

(2/3 times 6) times (p^4 times p^2) times (y^3 times y^4) times (s^5 times s^3)
(4) times (p^6) times (y^7) times (s^8)
4p^6y^7s^8

8 0
3 years ago
Find the greatest common factor of the following monomials 26n5 12n2
Sidana [21]

The greatest common factor is 2n^{2}


We first have to look for the largest number that goes into both equations. The factors of 12 are 1, 2, 3, 4, 6 and 12. None of 3, 4, 6, or 12 go into 26 evenly. So 2 is the largest number you can take out.


With the variables, we take out as many as the lowest number will let us. Since the smallest number of n's is 2 in the second term, we take that many.

8 0
3 years ago
Mia tossed a penny, a nickel, and a dime. Which is a complete tree diagram for all possible outcomes, where H represents heads a
Novay_Z [31]

Mia tossed a penny,a nickel and a dime all possible outcomes of H is the answer C.

Step-by-step explanation:

  • The two possible outcomes for penny,nickel and dime is H & T.
  • H is for head T is for tail.
  • Let A {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
  • Tossing a fair coin will give the above result.
  • S is the called the n number of outcomes that are available for a set.
  • Total outcome of Sample space 8.
  • The three diagram is like a game theory it exploits different outcome.
8 0
3 years ago
What’s the answer ?
elena-14-01-66 [18.8K]

Answer:

It is 9x^3.

Step-by-step explanation:

36x^4 and 45x^3.

GCF of 36 and 45 = 9

GCF of x^4 and x^3 = x^3

GCF of 36x^4 and 45x^2 = 9x^3.

7 0
3 years ago
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