Round off 19340 to 1 s f

How to factor this expression <br><br>x^3 - 4x^2 + 4x - 16

Natalija [7]

X²(x - 4) +4 (x - 4)

(x² + 4) (x - 4)

First find the common terms that can enter into both x³ and 4x² then write its down in this case it’s x² that can enter x³ leaving only x _since x³/x² = subtract of the indices. x² will also enter 4x² leaving only four hence you having x² (x - 4)
then do the same for the next pair of terms giving you 4 that can enter into both 4 and 16
Leaving you with +4 (x - 4)

Now you can put the common terms together like so (x² + 4) and choose get one of the other two which are the same= (x - 4)
= (x² + 4) (x - 4)

8 0

2 years ago

Translate (3,2) to the left one unit. Then reflect the result over the y-axis. What are the coordinates of the final point?

OleMash [197]

Answer:

(-2, 2)

Step-by-step explanation:

Take point (3, 2) and first translate it left one unit. Now the point is (2, 2)

Now reflect it over the y-axis. Doing so keeps the y value the same, we have a vertical line of reflection, so we are only changing the distance to the y-axis, which is the x-value.

Our x value is 2 units away from the y axis, so its reflection will be 2 units away on the other side of the axis.

The new x value is -2, so the point is (-2, 2)

4 0

2 years ago

Helpppppppppppppppppppppppppp

nikklg [1K]

Answer:

um

Step-by-step explanation:

hehhhhhhhhhhhhhhhhhhhhhhhh

5 0

3 years ago

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random

frez [133]

Answer: $H_0 : \mu=50\\\\ H_1 : \mu\neq50$

Step-by-step explanation:

An null hypothesis ( $H_0$ ) is a statement of equality which shows that there is no statistical difference between the groups being tested.

An alternative hypothesis ( $H_1$ ) is a statement of inequality which shows that there is statistical difference between the groups being tested.

Let $\mu$ be the population mean amount of garbage per bin .

Given : A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50.

i.e. $\mu\neq 50$ → Alternative

Thus , the appropriate null and alternative hypotheses :

$H_0 : \mu=50\\\\ H_1 : \mu\neq50$

6 0

3 years ago

The Damon family owns a large grape vineyard in western New York along Lake Erie. The grapevines must be sprayed at the beginnin

vazorg [7]

Answer:

$z=\frac{0.0955-0.0611}{\sqrt{0.08(1-0.08)(\frac{1}{440}+\frac{1}{360})}}=1.784$

$p_v =2*P(Z>1.784) =0.074$

Comparing the p value with the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the two proportions differes at 10% of significance.

Step-by-step explanation:

Data given and notation

$X_{1}=42$ represent the number of infested vines for Pernod5

$X_{2}=22$ represent the number of infested vines for Action

$n_{1}=440$ sample of Pernod5

$n_{2}=360$ sample of Action

$\hat p_{1}=\frac{42}{440}=0.0955$ represent the proportion of residents of infested vines for Pernod5

$\hat p_{2}=\frac{22}{360}=0.0611$ represent the proportion of infested vines for Action

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.1$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference between thw two population proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} - p_{2}=0$

Alternative hypothesis: $p_{1} - p_{2} \neq 0$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{1}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{42+22}{440+360}=0.08$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.0955-0.0611}{\sqrt{0.08(1-0.08)(\frac{1}{440}+\frac{1}{360})}}=1.784$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>1.784) =0.074$

Comparing the p value with the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the two proportions differes at 10% of significance.

4 0

3 years ago

Round off 19340 to 1 s f​

Round off 19340 to 1 s f