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VikaD [51]
3 years ago
5

Solve for h. s=6πsh+6πs²

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

Try h=(1-6πs)/6π

Step-by-step explanation:

That's the same answer in another format

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An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 3.6
Natali [406]

Answer:

She must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.

Step-by-step explanation:

We are given that an engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation is 3.6 mm.

And she considers to be 90% sure of knowing the mean will be within ±0.1 mm.

As we know that the margin of error is given by the following formula;

The margin of error =  Z_(_\frac{\alpha}{2}_) \times \frac{\sigma}{\sqrt{n} }  

Here, \sigma = standard deviation = 3.6 mm

         n = sample size of components

         \alpha = level of significance = 1 - 0.90 = 0.10 or 10%

         \frac{\alpha}{2} = \frac{0.10}{2} = 0.05 or 5%

Now, the critical value of z at a 5% level of significance in the z table is given to us as 1.645.

So, the margin of error =  Z_(_\frac{\alpha}{2}_) \times \frac{\sigma}{\sqrt{n} }  

                  0.1 mm        =  1.645 \times \frac{3.6}{\sqrt{n} }

                    \sqrt{n} =  \frac{3.6\times 1.645}{0.1 }

                    \sqrt{n} = 59.22

                     n = 59.22^{2} = 3507.0084 ≈ 3507.

Hence, she must consider 3507 components to be 90% sure of knowing the mean will be within ± 0.1 mm.

8 0
4 years ago
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