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Scilla [17]
3 years ago
9

At 5:00 a.m., the temperature outside was 6°F below zero. By noon, it rose by 15°F.

Mathematics
1 answer:
irina [24]3 years ago
6 0

Answer:

The evening temperature is 4° F

Step-by-step explanation:

6° F below 0 =  -6.

15° F. -6 + 15 is 9.

9° F. 5° F. 9 - 5 = 4

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I made a punch with 3 parts ginger ale to 2 parts HI-C. I need 20oz. of punch. How much HI-C do I need?
Lapatulllka [165]

You need 20 oz. of punch with 3 parts ginger ale and 2 parts HI-C. So the end result will have 5 parts. To find out how many ounces are in each part, just divide the total (20) by the number of parts (5):

20 / 5 = 4

There will be 4 ounces per part.

First, solve for the amount of ginger ale. The problem says the punch is 3 parts ginger ale, so just multiply the number of parts by the amount in each part:

(3)(4) = 12

The punch will have 12 ounces of ginger ale.

Next, solve for the amount of HI-C. The problem says the punch is 2 parts HI-C, so just multiply the number of parts by the amount in each part:

(2)(4) = 8

The punch will have 8 ounces of HI-C.

Hope this helps!

3 0
3 years ago
Determine the slope of the line shown.
Pani-rosa [81]
(0,2),(2,-1)
slope = (-1 - 2) / (2 - 0) = -3/2 <==
6 0
3 years ago
What is reasonable estimate for the problem
vlabodo [156]

Answer:

-2

Step-by-step explanation:

this is i ready lol but basically the actual answer is -1.5 but if you round that you get -2

8 0
4 years ago
Read 2 more answers
What fractions are equivalent to 6/12
kirill [66]

Answer:

Step-by-step explanation:

1

2

is equivalent to 6

12

because 1 x 12 = 2 x 6 = 12

2

4

is equivalent to 6

12

because 2 x 12 = 4 x 6 = 24

3

6

is equivalent to 6

12

because 3 x 12 = 6 x 6 = 36

4

8

is equivalent to 6

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because 4 x 12 = 8 x 6 = 48

7 0
3 years ago
2logx=3-2log(x+3) solve for x​
AVprozaik [17]

Answer:

\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}

Step-by-step explanation:

2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}

x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D

6 0
3 years ago
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