Answer :When rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates. When prices are expressed as a quantity of 1, such as $25 per ticket or $0.89 per can, they are called unit prices.
Step-by-step explanation:
Answer:
![3x^2-9xy+13y^2](https://tex.z-dn.net/?f=3x%5E2-9xy%2B13y%5E2)
Step-by-step explanation:
We begin with : ![6x^2-7xy+8y^2-[(x^2-3xy-y^2)+(2x^2+5xy-4y^2)]](https://tex.z-dn.net/?f=6x%5E2-7xy%2B8y%5E2-%5B%28x%5E2-3xy-y%5E2%29%2B%282x%5E2%2B5xy-4y%5E2%29%5D)
First, let us add the two portions within the brackets. To do this, we need to just combine the like terms
![6x^2-7xy+8y^2-[(x^2-3xy-y^2)+(2x^2+5xy-4y^2)]\\\\6x^2-7xy+8y^2-[3x^2+2xy-5y^2]](https://tex.z-dn.net/?f=6x%5E2-7xy%2B8y%5E2-%5B%28x%5E2-3xy-y%5E2%29%2B%282x%5E2%2B5xy-4y%5E2%29%5D%5C%5C%5C%5C6x%5E2-7xy%2B8y%5E2-%5B3x%5E2%2B2xy-5y%5E2%5D)
Next, we need to distribute the negative to all the terms within the brackets
![6x^2-7xy+8y^2-[3x^2+2xy-5y^2]\\\\6x^2-7xy+8y^2-3x^2-2xy+5y^2](https://tex.z-dn.net/?f=6x%5E2-7xy%2B8y%5E2-%5B3x%5E2%2B2xy-5y%5E2%5D%5C%5C%5C%5C6x%5E2-7xy%2B8y%5E2-3x%5E2-2xy%2B5y%5E2)
Now we can combine the like terms again
![6x^2-7xy+8y^2-3x^2-2xy+5y^2\\\\3x^2-9xy+13y^2](https://tex.z-dn.net/?f=6x%5E2-7xy%2B8y%5E2-3x%5E2-2xy%2B5y%5E2%5C%5C%5C%5C3x%5E2-9xy%2B13y%5E2)
Answer:
48
Step-by-step explanation:
G:B Total
3:4 7
36 divided by 3 is 12.
12 x 4 = 48
In total there are 84 tokens in the bag, 48 of which are black and 36 are green.
Answer:
The sales for the store 7 days after the end of the advertising campaign is
$3849.74
Step-by-step explanation:
From the question we are told that
The daily sales on the end of campaign day is
= $8,500
The daily sales three days after end of campaign day is
= $ 5,100
The usual day sales of the store is
= $ 3,500
Generally the Newton's Law of Cooling (Heating). equation is mathematically represented as
![G_t = G_u+ [(G_o -S_u ) * e^{-(k*t)}]](https://tex.z-dn.net/?f=G_t%20%3D%20%20G_u%2B%20%20%5B%28G_o%20-S_u%20%29%20%2A%20%20e%5E%7B-%28k%2At%29%7D%5D)
Here t is the number of day after the campaign ended
Now substituting values to obtain the constant k
For t = 3
![G_3 = G_u + [(G_o -S_u ) * e^{-(k*3)}]](https://tex.z-dn.net/?f=G_3%20%3D%20%20G_u%20%20%2B%20%5B%28G_o%20-S_u%20%29%20%2A%20%20e%5E%7B-%28k%2A3%29%7D%5D)
![5100 = 3500 [(8500 -3500 ) * e^{-(k*3)}]](https://tex.z-dn.net/?f=5100%20%3D%20%203500%20%20%5B%288500%20%20-3500%20%29%20%2A%20%20e%5E%7B-%28k%2A3%29%7D%5D)
![e^{-(k*3)} = 0.32](https://tex.z-dn.net/?f=e%5E%7B-%28k%2A3%29%7D%20%3D%20%200.32)
=> ![-3k = ln (0.6)](https://tex.z-dn.net/?f=-3k%20%3D%20%20ln%20%280.6%29)
=> ![-3k = -1.1394](https://tex.z-dn.net/?f=-3k%20%3D%20%20-1.1394)
=> ![k = 0.380](https://tex.z-dn.net/?f=k%20%20%3D%200.380)
So at t = 7
![G_7 = G_u + [(G_o -S_u )] * e^{-(k*7)}](https://tex.z-dn.net/?f=G_7%20%3D%20%20G_u%20%20%2B%20%5B%28G_o%20-S_u%20%29%5D%20%2A%20%20e%5E%7B-%28k%2A7%29%7D)
substituting values
![G_7 = 3500 + [(8500 -3500 )] * e^{-(0.3780*7)}](https://tex.z-dn.net/?f=G_7%20%3D%20%203500%20%20%2B%20%5B%288500%20-3500%20%29%5D%20%2A%20%20e%5E%7B-%280.3780%2A7%29%7D)
$3849.74
The answer of the equation when a is plugged in to the answer is 27.5.