Answer:
We have function,
Standard Form of Sinusoid is
Which corresponds to
where a is the amplitude
2pi/b is the period
c is phase shift
d is vertical shift or midline.
In the equation equation, we must factor out 2 so we get
Also remeber a and b is always positive
So now let answer the questions.
a. The period is
So the period is pi radians.
b. Amplitude is
Amplitude is 6.
c. Domain of a sinusoid is all reals. Here that stays the same. Range of a sinusoid is [-a+c, a-c]. Put the least number first, and the greatest next.
So using that<em> rule, our range is [6+3, -6+3]= [9,-3] So our range</em> is [-3,9].
D. Plug in 0 for x.
So the y intercept is (0,-3)
E. To find phase shift, set x-c=0 to solve for phase shift.
Negative means to the left, so the phase shift is pi/4 units to the left.
f. Period is PI, so use interval [0,2pi].
Look at the graph above,
Answer:
(4x - 6)(y + 1)
Step-by-step explanation:
Group them: (4xy + 4x) (-6y - 6)
Take out the greatest common factor for both:
4x(y + 1) -6(y + 1)
Put it together: (4x - 6) (y + 1) (y + 1)
Since there are two (y + 1)'s, you can get rid of one, giving you:
(4x - 6) (y + 1)
4 1/2(2)=9. Multiply by 2 to get total
9- 3 1/2=z. Subtract 3 1/2 from total to get Z
5 1/2= Z
Assume that the pillars are cylindrical..you're looking for the lateral surface area correct?
to get the lateral surface area, you use the formula LSA = 2rh(pi) where r is radius h is height
substitute the values...
h = 10
d = 1 so r =1/2
so LSA = 2 (1/2)(10)(3.14)
LSA = 10(3.14)
LSA = 31.4 sq ft :D Can You Mark Me Brainlest Plz...
Answer:
Hey there!
For the first question we use the triangle area formula: 1/2bh, or 1/2(8)(5). This gives us 20 for the area.
For the second question we get a trapezoid, since the cross section does not pass through the vertex.
Hope this helps :)
