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ch4aika [34]
3 years ago
11

Write (2x)^4 without exponents

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
8 0

Answer:

16x^4

Step-by-step explanation:

Veronika [31]3 years ago
4 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

[see below]

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

\boxed{\text{Simplifying the Expression:}}\\\\(2x)^4\\----------------\\\rightarrow (2x)^4 \text{ is 2x multiplied 4 times.}\\\\\rightarrow (2x)^4 = \boxed{2x * 2x * 2x * 2x}\\\\\rightarrow 2x * 2x * 2x * 2x = \boxed{16*x^4}\\\\\rightarrow 16*x^4 = \boxed{16 * x * x * x * x}\\\\\text{The boxed answers with exception to the second one could be possible answers.}

»»————- ★ ————-««

⸻⸻⸻⸻

Hope this helps you. I apologize if it’s incorrect.  

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F(x)=-2x-1 and g(x)=x^2-1. Find (fog)(-5).
serg [7]

Answer: - 49

Step-by-step explanation:

f(x) = -2x - 1

g(x) = x^{2} - 1

fg(x) = f (x^{2} - 1) , we just put in the value of g(x) , the next thing is to substitute x^{2} - 1 for the value of x in f(x) , that is

fg(x) = -2(x^{2} - 1) - 1

fg(x) = -2x^{2} + 2 - 1

fg(x) = -2x^{2} + 1

Therefore : fg(-5) means we will substitute -5 for x in fg(x) , that is

fg(-5) = -2 ((-5)^{2} + 1

fg(-5) =  -2(25) + 1

fg(-5) = -50 + 1

fg(-5) = -49

7 0
4 years ago
Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11
Yanka [14]

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.

3 0
3 years ago
What is (6*2)+12*2/4
pishuonlain [190]

Answer:

(6)(2)+

(12)(2)

4

=18

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
30 POINTS! PLEASE HELP!
Masteriza [31]

Answer:

y=3x+(-6)

Step-by-step explanation:

y=mx+b

b is the initial condition which means any the point where the slope crosses the y axes.

m is the growth, also known as how much y increases when x increases by 1.

8 0
3 years ago
Evaluate :<br> A. <img src="https://tex.z-dn.net/?f=x%5E%7Bx%5E3%7D%3D3" id="TexFormula1" title="x^{x^3}=3" alt="x^{x^3}=3" alig
sdas [7]

Answer:

<h3>A. </h3>
  • x^{x^3} = 3
  • log x^{x^3} = log 3
  • x³ log x = log 3
  • 3x³ log x = 3 log 3
  • x³ log x³ = log 3³
  • x^3^{x^3} = 3³
  • x³ = 3
  • x = 3^{1/3}
<h3>B.</h3>
  • 4ˣ + 6ˣ = 9ˣ
  • 2²ˣ + 2ˣ3ˣ = 3²ˣ

<u>Divide both sides by 2²ˣ</u>

  • 1 + (3/2)ˣ = (3/2)²ˣ

<u>Substitute (3/2)ˣ = t</u>

  • t² - t - 1 = 0

<u>Solve for t:</u>

  • t = (1  ± √5)/2

<u>Positive root is considered as (3/2)ˣ can't be negative.</u>

  • (3/2)ˣ = (1 + √5)/2
  • x = log [(1 + √5)/2] / log (3/2)
  • x = 1.18681439028

7 0
3 years ago
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