So, monthly expenses = 1120+600+140/12 = 1731.667 = 1732
and his monthly income = 840×2 = 1680
so there is a surplus of 52
and I guess the answer will be first one by options you gave !!
Answer: How do you find you four consecutive odd integers such as three times the sum of the first and the second is 15 less than the fourth?
Step-by-step explanation: So, the normal consecutive integers numbers are: 2,3,4,5. And the even consecutive integers numbers are: 2,4,6,8. And the odd consecutive integers are: 3,5,7,9. Consecutive integers formula are the algebraic representations of the consecutive integers. The formula to get a consecutive integer is n + 1.
Same as above, 7 is one of 4 consecutive integers, then the result is only 4 cases:
, 5, 6, 7
, 6, 7, 8
, 7, 8, 9
, 8, 9, 10
Hope this helps.
Answer:
16 singles, 56 couples
Step-by-step explanation:
There's two linear equations that we can make: one for money and one for people.
Let the number of single tickets be s and the number of couple tickets be c
.
We know that the amount of money we make is $ = 20
s
+
35
c
=
2280
We also how many people can come P =
1
s
+
2
c
=
128
We know that both s are the same and both c are the same. We have two unknowns and two equations, so we can do some algebra to solve for each.
Take the first minus twenty times the second:
20
s
+
35
c =2280
−
20
s
−
40
c
=
−
2560
−
5
c
=
−
280
⇒
c
=
56
Plugging this back into the second equation,
s
+
2
c
=
s
+
2
⋅
56
=
s
+
112
=
128
⇒
s
=
16
Answer:
$93. mark brainliest if correct please! (If not 93, then it's gotta be 43)
Substitute the f(x) and g(x) following the required operations:
A. (f+g)x = (x^2 + 1) + (x + 1) = x^2 + x + 2
B. (f-g)x = (x^2 + 1) - (x + 1) = x^2 - x
C. (fg)x = (x^2 + 1)(x + 1) = x^3 + x^2 + x + 1
D. (f/g)x = (x^2 + 1) / (x + 1) or x - 1 + 2/(x+1) if answer must be in expanded form
E. (f o g)x = (x+1)^2 + 1 = x^2 + 2x + 2
F. (g o f)x = (x^2 + 1) + 1 = x^2 + 2
