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nata0808 [166]
3 years ago
12

3(-2-4v)<-90 help I'm stuck on this one ​

Mathematics
1 answer:
Pavel [41]3 years ago
5 0
Well, if you disregard the signs for a second, you can work this like a normal equation:
-6 - 12v = 90
-12v = 96
v = 8
Now just reincorporate the less than sign:
v < 8
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Eric had a total of 40 nickels and dimes if the total value of the coins is 330 cents, how many nickels and dimes does he have?
kumpel [21]

Answer:

165 of nickels and 165 of dimes

7 0
2 years ago
A potted tree weighs 21 pounds. The pot weighs 3 pounds. If w represents the weight of the tree without the pot, write an equati
masha68 [24]
W = 21 - 3
weight of the tree = 21 pounds - 3 pounds
8 0
3 years ago
Two cruise ships leave the same port with a 35° angle between their path. Cruise A is traveling at 18 miles per hour and Cruise
GuDViN [60]

Answer:

20\:\mathrm{miles}

Step-by-step explanation:

After travelling two hours, the two cruise ships form a triangle. One of the legs  of this triangle will be the distance Cruise A travelled, and another will be the distance Cruise B travelled. We can find the distance they travel using:

s=\frac{d}{t}, d=s\cdot t

Cruise A is travelling at 18 miles per hour for 2 hours. Therefore, Cruise A has travelled:

d=s\cdot t=18\cdot 2=36\:\mathrm{miles}

Cruise B is travelling at 15 miles per hour for 2 hours. Therefore, Cruise B has travelled:

d=s\cdot t=15\cdot 2=30\:\mathrm{miles}

Because we are given the angle between these legs, we can use the Law of Cosines to find the third leg. The Law of Cosines is given by:

c^2=a^2+b^2-2ab\cos C, where a, b, and c are interchangeable. Let c represent the distance between the two cruises. We have:

c^2=36^2+30^2-2\cdot36\cdot30\cdot \cos 35^{\circ},\\c^2=426.63,\\c\approx \fbox{$20\:\mathrm{miles}$}(one significant figure).

8 0
2 years ago
Read 2 more answers
WILLL GIVE A BRAINLEST
lord [1]

It is B. simple random sample

5 0
3 years ago
Read 2 more answers
The specification for the pull strength of a wire that connects an integrated circuit to its frame is 10 g or more. In a sample
Wittaler [7]

Answer:

The 95% confidence interval for the difference is (-0.1888, 0.0202).

Step-by-step explanation:

Difference between proportions:

The distribution of the difference between two proportions has mean of the difference between these proportions and standard deviation is the square root of the sum of the variances. So

In a sample of 86 units made with gold wire, 68 met the specification

This means that:

pX = \frac{68}{86} = 0.7907

sX = \sqrt{\frac{0.7907*0.2093}{86}} = 0.0439

In a sample of 120 units made with aluminum wire, 105 met the specification.

This means that:

pY = \frac{105}{120} = 0.875

sY = \sqrt{\frac{0.875*0.125}{120}} = 0.0302

Difference:

p = pX - pY = 0.7907 - 0.875 = -0.0843

s = \sqrt{sX^2 + sY^2} = \sqrt{0.0439^2+0.0302^2} = 0.0533

Confidence interval:

p \pm zs

In which z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}, with \alpha being 1 subtracted by the confidence level.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Lower bound of the interval:

p - zs = -0.0843 - 1.96*0.0533 = -0.1888

Upper bound of the interval:

p + zs = -0.0843 + 1.96*0.0533 = 0.0202

The 95% confidence interval for the difference is (-0.1888, 0.0202).

6 0
2 years ago
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