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Dimas [21]
3 years ago
6

This is the answer but can someone do the work plss??

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0
Try using the app/website Cymath, it tells you the work! :)
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P(x) is a polynomial. here are a few values of p(x).
Diano4ka-milaya [45]

Given:

Values of a polynomial P(x).

P(-5)=-2

P(-3)=6

P(3)=7

P(5)=-1

To find:

The remainder when P(x) is divided by (x+5).

The remainder when P(x) is divided by (x-3).

Solution:

If a polynomial P(x) is divided by (x-a), then the remainder is P(a).

If the polynomial P(x) is divided by (x+5), then the remainder is P(-5).

P(-5)=-2

Therefore, the remainder is -2 when P(x) is divided by (x+5).

If the polynomial P(x) is divided by (x-3), then the remainder is P(3).

P(3)=7

Therefore, the remainder is 7 when P(x) is divided by (x-3).

3 0
3 years ago
Find the missing angle according to the Triangle Sum Theorem.
Lynna [10]
The answers to the missing angle is 40°
4 0
3 years ago
If log a=x and logb=y, then log √ab is equivalent to
mr_godi [17]
The answer to this equation would be approximately 55
8 0
3 years ago
The base of the triangular flag was 4ft and the height was 3 feet. What is the area of Karmas flag
Lilit [14]

Answer:

6 ft.^{2}

Step-by-step explanation:

Use the triangle area equation

A=\frac{b*h}{2}

plug in the base (4ft) times the height (3ft) then divide by two

8 0
3 years ago
Dogs in the GoodDog Obedience School win a blue ribbon for learning how to sit, a green ribbon for learning how to roll over, an
tiny-mole [99]

Answer:

  5

Step-by-step explanation:

The 32 that have blue and green ribbons include the 16 that have all three, so there are only 32 -16 = 16 that have only blue and green ribbons.

The 31 that have green and white ribbons likewise include the 16 with all three, so there are only 31 -16 = 15 that have only green and white ribbons.

The 38 that have blue and white ribbons include the 16 with all three, so there are only 38 -16 = 22 that have only green and white ribbons.

__

If we add the numbers of blue, green, and white ribbons, we are counting twice the numbers that have 2 ribbons, and 3 times the numbers that have 3 ribbons. We want to count each kind of ribbon-holder only once. Hence the number of individual dogs with any number of ribbons is only ...

  62 +55 +63 -(16 +15 +22) -2(16) = 95

Of the 100 dogs, 95 have ribbons, so 5 dogs have not learned any tricks.

7 0
4 years ago
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