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vazorg [7]
3 years ago
14

A rock falls from a tower that is 416 ft high. As it is falling, its height is given by the formula h=416-16t^2. How many second

s will it take for the rock to hit the ground (h=0)?
Mathematics
1 answer:
slava [35]3 years ago
4 0
5.1 Seconds. t = 5.1

5.1^2 = 26.01

416/16 = 26

26*16 = 416
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PLEASE HELP!! Please show your work in explanation no nonsense or blank answers please ;)
krok68 [10]

Answer:

r = 4.908

Step-by-step explanation:

V  = 885

height (given in the picture) = 11.7

V = \pi r^2h

V = (3.14)(r^2)(h)

885 = (3.14)(r^2)(11.7)

885/3.14/11.7 = r^2

Take the square root and you get 4.908.

8 0
3 years ago
Given the tables for f & g below, find the following: x f ( x ) g ( x ) 0 9 7 1 4 8 2 3 6 3 5 1 4 7 5 5 1 2 6 6 0 7 0 4 8 2
d1i1m1o1n [39]

\\(i)\\
\text{We know that the average rate of change of a function f(x) on inerval [a,b] is}\\
\\
f_{avg}=\frac{f(b)-f(a)}{b-a}\\
\\
\text{so using this the average rate of chang of g for x on interval }[3,7] \text{ is}\\
\\
g_{avg}=\frac{g(7)-g(3)}{7-3}\\
\\
=\frac{4-1}{4}\\
\\
=\frac{3}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{3}{4}

\\(ii)\\  \text{Average rate of chang of f for x on interval }[3,7] \text{ is}\\
\\
f_{avg}=\frac{f(7)-f(3)}{7-3}\\
\\
=\frac{0-5}{4}\\
\\
=\frac{-5}{4}\\
\\
\text{so average rate of change of g on interval [3,7] is }\frac{-5}{4}

\\(iii)\\
\text{Since g(4)=5, so we have}\\
\\
f(g(4))=f(5)\\
\\
\text{since the value of f is 1 at x=5. so }\\
\\
f(g(4))=f(5)=1\\
\\
\text{hence we have, }f(g(4))= 1

\\(iv)\\
\text{Since f(3)=5, so we have}\\
\\
g(f(3))=g(5)\\
\\
\text{since the value of g is 2 at x=5. so }\\
\\
g(f(3))=g(5)=2\\
\\
\text{hence we have, }g(f(3))= 2

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3 years ago
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The answer is 13......
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nexus9112 [7]

Answer:

answer x =2

Step-by-step explanation:

answer x=2

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3 0
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Answer:

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