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3 years ago

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Given equation of a circle: x^2 – 4x + y^2 + 6y = 12 rewrite it in a standard form. Find its radius and coordinates of its cente

r. Standard Form:_____
r:_____

Center:____

1 answer:

Yuki888 [10]3 years ago

7 0

Answer:

<u>The standard form is:</u>

(x - h)² + (y - k)² = r², where (h, k) is the center, r is the radius

<u>Convert the given into standard form by completing square:</u>

x² - 4x + y² + 6y = 12
x² - 4x + 4 + y² + 6y + 9 = 12 + 4 + 9
(x - 2)² + (y + 3)² = 25
(x - 2)² + (y + 3)² = 5²

The standard form is above.
The center is (h, k) = (2, -3)
The radius is r = 5

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