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andrew-mc [135]

3 years ago

10

Help ASAP please :)) Image attached

1 answer:

NemiM [27]3 years ago

4 0

No Sophie made a mistake going from step one to two. (She should’ve multiplied 9*2 and 6*7 instead of dividing first, she didn’t follow PEMDAS)

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WILL GIVE BRAINLIEST!

madam [21]

Answer:

B: 4 liters of soda

Step-by-step explanation:

16 / 4 = 4

Therefore,

The snack committee mixed 4 liters of soda per liter of fruit punch.

5 0

4 years ago

Read 2 more answers

A dartboard consists of two concentric circles. The probability of hitting the inner circle is

stepan [7]

Given:
Diameter of outer circle = 20 inches.

We need to find the Area of the outer circle to get the radius of the inner circle.

Area = πr²

Outer circle Area = 3.14 * (10in)² = 314 in²

314 in² * 64% probability = 200.96 in² Area of the inner circle.

200.96 in² = 3.14 * r²
200.96 in² / 3.14 = r²
64 in² = r²
√64 in² = √r²
8 in = r

radius of inner circle is 8 inches.

3 0

3 years ago

What does w=11 plus negative 7

kow [346]

Answer:

w=4

Step-by-step explanation:

adding a negative is like subtracting so w=11-7

5 0

4 years ago

Read 2 more answers

You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t

rosijanka [135]

Answer:

$Height = 12cm$

$Radius = 6cm$

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

$V = 432\pi$

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

$V = \pi r^2h\\$

Substitute 432π for V

$432\pi = \pi r^2h$

Divide through by π

$432 = r^2h$

Make h the subject:

$h = \frac{432}{r^2}$

Surface Area (A) of a cylinder is calculated as thus:

$A=2\pi rh+2\pi r^2$

Substitute $\frac{432}{r^2}$ for h in $A=2\pi rh+2\pi r^2$

$A=2\pi r(\frac{432}{r^2})+2\pi r^2$

$A=2\pi (\frac{432}{r})+2\pi r^2$

Factorize:

$A=2\pi (\frac{432}{r} + r^2)$

To minimize, we have to differentiate both sides and set $A' = 0$

$A'=2\pi (-\frac{432}{r^2} + 2r)$

Set $A' = 0$

$0=2\pi (-\frac{432}{r^2} + 2r)$

Divide through by $2\pi$

$0= -\frac{432}{r^2} + 2r$

$\frac{432}{r^2} = 2r$

Cross Multiply

$2r * r^2 = 432$

$2r^3 = 432$

Divide through by 2

$r^3 = 216$

Take cube roots of both sides

$r = \sqrt[3]{216}$

$r = 6$

Recall that:

$h = \frac{432}{r^2}$

$h = \frac{432}{6^2}$

$h = \frac{432}{36}$

$h = 12$

Hence, the dimension that requires the least amount of material is when

$Height = 12cm$

$Radius = 6cm$

3 0

3 years ago

Type the correct answer in the box. Use numerals instead of words.

vazorg [7]

Answer:

30%

Step-by-step explanation:

plato

4 0

3 years ago