Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:
The amount earned is 2,600
Step-by-step explanation:
In order to find the commission amount, start by multiplying the percentage by the amount sold. Then to find the total amount, add the flat rate.
30,000*.02 = 600
Then add the flat rate
600 + 2,000 = 2,600
Answer:
61
Step-by-step explanation:
52 + 12 = 64
64-3 that left is 62 cars in the parking lot
Answer:
80
Step-by-step explanation:
Answer:
x = 6
Step-by-step explanation:
use alternate angles